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A rectangular lot is to be enclosed with a fence. A building is on one side of the lot, so it won't need any fencing. Find the dimensions of the field having the largest area that can be enclosed with 600 feet of fencing material. (A) 130 feet by 165 feet (B) 150 feet by 100 feet 150 feet by 75 feet (D) 150 feet by 300 feet

A rectangular lot is to be enclosed with a fence. A building is on one side of the lot, so it won't need any fencing. Find the dimensions of the field having the largest area that can be enclosed with 600 feet of fencing material. (A) 130 feet by 165 feet (B) 150 feet by 100 feet 150 feet by 75 feet (D) 150 feet by 300 feet

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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A rectangular lot is to be enclosed with a fence. A building is on one side of the lot, so it won't need any fencing. Find the dimensions of the field having the largest area that can be enclosed with 600 feet of fencing material. (A) 130 feet by 165 feet (B) 150 feet by 100 feet 150 feet by 75 feet (D) 150 feet by 300 feet
Transcribed Image Text:A rectangular lot is to be enclosed with a fence. A building is on one side of the lot, so it won't need any fencing. Find the dimensions of the field having the largest area that can be enclosed with 600 feet of fencing material. (A) 130 feet by 165 feet (B) 150 feet by 100 feet 150 feet by 75 feet (D) 150 feet by 300 feet
Find the local extrema of the function f defined by f (x) =x3– 3x2 – 9x A f(-1)=5 local minimum; f (3) = – 18 local maximum B f(-1) = - 13 local minimum; f (3) = – 27 local maximum (c f (-1) =5 local maximum; f(3) =- 27 local minimum D f(-1)=13 local maximum; f (3) = - 18 local minimum
Transcribed Image Text:Find the local extrema of the function f defined by f (x) =x3– 3x2 – 9x A f(-1)=5 local minimum; f (3) = – 18 local maximum B f(-1) = - 13 local minimum; f (3) = – 27 local maximum (c f (-1) =5 local maximum; f(3) =- 27 local minimum D f(-1)=13 local maximum; f (3) = - 18 local minimum
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