A rectangular block of height Land horizontal cross-sectional area A floats at the interface between twoimmiscible liquids, as shown below.Fluid 1Pi(g/em³)Fluid 2BlockP:(g/cm³)Po(g/cm³)(a) Derive a formula for the block density, Pp, in terms of the fluid densities p, and p2, the heightshọ. h1, and h2, and the cross-sectional area A. (It is not necessary that all of these variables appear inthe final result.)(b) Force balances on the block can be calculated in two ways: (i) in terms of the weight of the blockand the hydrostatic forces on the upper and lower block surfaces; and (ii) in terms of the weight ofthe block and the buoyant force on the block as expressed by Archimedes' principle. Prove thatthese two approaches are equivalent.

Given data as per question The density of the first fluid = p1 g/cm3 The density of second fluid =p2…

Answered: A rectangular block of height Land…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

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