A recent poll of debit cardholders in the U.S. found that 20% of debit cardholders had used their debit card to make a purchase on theinternet. In a random selection of 9 debit cardholders, find the probability that at most 1 had used their debit card to make a purchase.0.010,050,100,150,200.250,300,350.400.450.50n=9090.00460.03390,11100.21190.26000.21280.11600.04070.00830.00080.002080,38740.38740,17220.04460.00740.00080.01010.06050.07510.22530,30030.23360.11680.03890.00870.00120.00010.04040,15560.26680.26680.17150.07350.02100.00390.00040.91350,02070.63020.29850,06290,23160,36790,25970,10690.02830.00500.00060,13420.30200.30200.017670,08300.10040.21620,27160.21940,11810.07030.16410.24610.24610.16410.07030.161220.003430,00010,25080.25080.16720.07430.02120.00350.00030.00770.17620.06610.01650.00280.00030.00060.00010.04240.00980.00130.000120.01760.0020Find the mean and standard deviation of the number of debit cardholders that used their debit card to make a purchase on the internet.H= npo = /npqMean:Standard Deviation:

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Description: A recent poll of debit cardholders in the U.S. found that 20% of debit cardholders had used their debit card to make a purchase on theinternet. In a random selection of 9 debit cardholders, find the probability that at most 1 had used their debit ca

Answered: Image /qna-images/answer/50e611f2-9b9b-4887-aa69-7ea28c8dc073.jpgConsider a random variable X, defines the number of debit card holders. Here, n = the total number of debit card holders. There are total 9 debit card holders. It is given that, 20% of the debit card holders had used their debit card to make a purchase. Thus, the success probability is p = 0.2. In this case, there are two outcomes, such that, whether debit card holders had used their debit card to make a purchase or not. These two events are independent to each other, and the probabilities of success are independent for each trial. Thus, X follows Binomial distribution with number of trials n = 9 and success probability p = 0.2. The number of trials n = 9 and success probability p = 0.2. The mean is µ = np = (9)(0.2) = 1.8. The variance is σ2 = np(1 – p) = (9)(0.2)(1 – 0.2) = 1.44. The standard deviation is σ = √(np(1 – p)) = (√(1.44) = 1.2. The probability that at most 1 had used their debit card to make a purchase is, From the given table, corresponding to x = 0, n = 9 and p = 0.20 it is obtained that P(X = 0) = 0.1342. Thus, P(X ≥ 1) = 1 – P(X = 0) = 1 – 0.1342 = 0.8658. Thus, the probability that at most 1 had used their debit card to make a purchase is 0.8658.

Math

Statistics

A recent poll of debit cardholders in the U.S. found that 20% of debit cardholders had used their debit card to make a purchase on the internet. In a random selection of 9 debit cardholders, find the probability that at most 1 had used their debit card to make a purchase. 0.01 0,05 0.10 0.15 0.20 0.25 0,30 0,35 0.40 0.45 0.50 n=9 0 0.0207 0.1004 0.2162 0.2716 0.2194 0.1181 0.0424 0.0101 0.0605 0.1612 0.2508 0.2508 0.0046 0.0339 0.1110 0.2119 0.2600 0.2128 0.1160 0.0020 0,0176 0.0703 0.1641 5 0.9135 0.6302 0.2985 0,0629 0.0077 0.3874 0.3874 0,1722 0.0446 0.2316 0.3679 0.2597 0.1069 0.0751 0.2253 0,3003 0.2336 0.0404 0.1556 0.2668 0.2668 0.1715 0.0735 0.0210 0.1342 0.3020 0,3020 1 0.0830 2 0.0034 3 0.0001 0.1762 0.2461 4 0.0006 0.0074 0.0008 0.0001 0.0283 0.0050 0.0006 0.0661 0.1168 0.0389 0.0087 0.0012 0.0001 0.1672 0.0743 0.0212 0.0035 0.0003 0.2461 3 0.0165 0.0028 0.1641 0.0039 0.0004 2 0.0176 0.0020 0.0703 0.0407 0.0083 0.0008 0.0003 0.0098 0.0013 0.0001 1

A recent poll of debit cardholders in the U.S. found that 20% of debit cardholders had used their debit card to make a purchase on the internet. In a random selection of 9 debit cardholders, find the probability that at most 1 had used their debit card to make a purchase. 0.01 0,05 0.10 0.15 0.20 0.25 0,30 0,35 0.40 0.45 0.50 n=9 0 0.0207 0.1004 0.2162 0.2716 0.2194 0.1181 0.0424 0.0101 0.0605 0.1612 0.2508 0.2508 0.0046 0.0339 0.1110 0.2119 0.2600 0.2128 0.1160 0.0020 0,0176 0.0703 0.1641 5 0.9135 0.6302 0.2985 0,0629 0.0077 0.3874 0.3874 0,1722 0.0446 0.2316 0.3679 0.2597 0.1069 0.0751 0.2253 0,3003 0.2336 0.0404 0.1556 0.2668 0.2668 0.1715 0.0735 0.0210 0.1342 0.3020 0,3020 1 0.0830 2 0.0034 3 0.0001 0.1762 0.2461 4 0.0006 0.0074 0.0008 0.0001 0.0283 0.0050 0.0006 0.0661 0.1168 0.0389 0.0087 0.0012 0.0001 0.1672 0.0743 0.0212 0.0035 0.0003 0.2461 3 0.0165 0.0028 0.1641 0.0039 0.0004 2 0.0176 0.0020 0.0703 0.0407 0.0083 0.0008 0.0003 0.0098 0.0013 0.0001 1

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Concept explainers

Types of Bias

Statistics is the study of data collection, organization, analysis, interpretation, and presentation. Statistical bias is a characteristic of a statistical technique or its findings in which the expected value deviates from the actual root quantitative parameter being estimated. According to the actual definition of bias, it refers to the tendency of a statistic to overestimate or underestimate a parameter.

Topic Video

Question

A recent poll of debit cardholders in the U.S. found that 20% of debit cardholders had used their debit card to make a purchase on the
internet. In a random selection of 9 debit cardholders, find the probability that at most 1 had used their debit card to make a purchase.
0.01
0,05
0,10
0,15
0,20
0.25
0,30
0,35
0.40
0.45
0.50
n=90
9
0.0046
0.0339
0,1110
0.2119
0.2600
0.2128
0.1160
0.0407
0.0083
0.0008
0.0020
8
0,3874
0.3874
0,1722
0.0446
0.0074
0.0008
0.0101
0.0605
0.0751
0.2253
0,3003
0.2336
0.1168
0.0389
0.0087
0.0012
0.0001
0.0404
0,1556
0.2668
0.2668
0.1715
0.0735
0.0210
0.0039
0.0004
0.9135
0,0207
0.6302
0.2985
0,0629
0,2316
0,3679
0,2597
0,1069
0.0283
0.0050
0.0006
0,1342
0.3020
0.3020
0.0176
7
0,0830
0.1004
0.2162
0,2716
0.2194
0,1181
0.0703
0.1641
0.2461
0.2461
0.1641
0.0703
0.1612
2
0.0034
3
0,0001
0,2508
0.2508
0.1672
0.0743
0.0212
0.0035
0.0003
0.0077
0.1762
0.0661
0.0165
0.0028
0.0003
0.0006
0.0001
0.0424
0.0098
0.0013
0.0001
2
0.0176
0.0020
Find the mean and standard deviation of the number of debit cardholders that used their debit card to make a purchase on the internet.
H= np
o = /npq
Mean:
Standard Deviation:

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