A recent Gallup poll consisted of 939   randomly selected adults who were asked whether​ "cloning of humans should or should not be​ allowed." Results showed that 803   of those surveyed indicated that cloning should not be allowed. Construct a​ 99% confidence interval estimate of the proportion of all people who say they are opposed to cloning. a. What is the sample​ size? n​ = nothing   b. Calculate the sample​ proportion: ModifyingAbove p with caret equals nothing   ​(round to 3 decimal​ places)   c. Calculate ModifyingAbove q with caret equals nothing   ​(round to 3 decimal​ places)   d. What is the critical​ value? z Subscript alpha divided by 2 Baseline equals nothing   ​(use 3 decimal​ places)   e. Calculate the margin of​ error: E​ = nothing   ​(round to 3 decimal​ places)   f. Find the confidence​ interval: nothing less than p less thannothing   ​(round to 3 decimal​ places)   g. Do your results suport the claim that a majority of adults are opposed to such​ cloning? Why or why​ not?     A. ​Yes, because ModifyingAbove p with caret   is close to 0.5   B. ​No, because   ModifyingAbove p with caret   is greater than 0.5   C. ​No, because the lower confidence interval limit is above 0.5   D. ​Yes, because the lower confidence interval limit is above 0.5

Q: a. A random sample of 180 students from a private kindergarten produces mean weight of 46.3kg with…

A: Data given (a)  n=sample size=180, sample mean x̄=46.3, sample standard deviations s=4.7

Q: Refer to the data set of 20 randomly selected presidents given below. Treat the data as a sample and…

A: Given that            sample size, n=20 Here, we have to construct a​ 95% confidence interval…

Q: A poll reported 30% support for a statewide election with a margin of error of 3.96 percentage…

A: Given  p^=30%, margin of error=e=3.96% , Level of the significance=0.05

Q: poll reported 41% support for a statewide election with a margin of error of 1.72 percentage points.…

A: We have given that  Population proportion p =41%=0.41 Margin of error =E =1.72%=0.0172 90%…

Q: A national air traffic control system handled an average of 47,189 flights during 29 randomly…

A: The sample size is 29The sample mean is 47189The sample standard deviation is 6351We have to…

Q: In a study of government financial aid for college students, it becomes necessary to estimate the…

A: Given information : Margin of error (E) = 0.01 Level of significance = α = 0.10 critical value =zα2…

Q: find the sample size needed to estimate the percentage of democrats who have tattoos. Use a 0.05…

A:

Q: The Centers for Disease Control reported the percentage of people 18 years of age and older who…

A: a) The sample size can be estimated as follows: n=ze2p(1-p)where, z = z scoree = errorp =…

Q: A poll for a statewide election has a margin of error of 2.14 percentage points. How many voters…

A: From the provided information,Margin of error (E) = 0.0214Confidence level = 99%

Q: A random sample of 8 colleges was taken. The mean debt after graduation was ​$18,879 with a margin…

A: Given that,The sample size is  The mean debt after graduation is The margin of error is

Q: A survey of several 10 to 11 year olds recorded the following amounts spent on a trip to the mall:…

A: Confidence interval:The (1-α) 100% confidence interval for population mean µ is given by:

Q: We are trying to estimate the average lifespan of all Neanderthal humans who lived 100,000 years…

A: Given: Sample of 56 skeletons from caves and construct a 95% confidence interval for their…

Q: A poll reported 38% support for a statewide election with a margin of error of 1.36 percentage…

A: Proportion of voters who supports for a statewide election Margin of error Confidence level

Q: Announcements for 84 upcoming engineering conferences were randomly picked from a stack of IEEE…

A: Solution-: Given: n=84,x¯=3.94,s=1.28 We want to (1) In words define the random variable X and  X¯ ?…

Q: Refer to the data set of 20 randomly selected presidents given below. Treat the data as a sample and…

A: From the information out of 20 randomly selected presidents 8 are  taller than their opponents.

Q: According to a survey, 66% of all students in the U. S. own a laptop. For a simple random sample of…

A: It is given that, According to a survey, 66% of all students in the U. S. own a laptop i.e. the…

Q: A study of 420,063cell phone users found that 134 of them developed cancer of the brain or nervous…

A: Given: n = 420,063 p = 0.0323 Formula Used: Confidence Interval = p ± Zα/2p(1-p)n

Q: A survey of several 9 to 11 year olds recorded the following amounts spent on a trip to the mall:…

A: From the provided information,Sample size (n) = 7Confidence level = 95%

Q: On September 14, 2000, a cross-sectional survey of 24,000 residents of a western state revealed that…

A: Given: n = 24000 Number of tuberculosis cases X = 145 Proportion p^ = Xn Formula Used: Confidence…

Q: In 2010, the proportion of Texans without health insurance was 0.11. To update this information a…

A:

Q: A poll reported 60% support for a statewide election with a margin of error of 3.35  percentage…

A: The question is about sample size estimationGiven :Proportion of voters who supports for a statewide…

Q: A poll reported 37% support for a statewide election with a margin of error of 4.18 percentage…

A:

Q: Refer to the data set of 20 randomly selected presidents given below. Treat the data as a sample and…

A: Out of the given sample of size, n = 20 the number of presidents whose heights were more than their…

Q: a. A random sample of 180 students from a private kindergarten produces mean weight of 46.3kg with…

A:

Q: It is believed that slightly over 50% of Americans own pets. A 95% confidence interval for the…

A: Confidence Interval: The form of the confidence interval is, CI = Point estimate ± Margin of error…

Q: Out of 67,410 surgeries tracked in a study in the U.K., 2832 were followed by surgical site…

A: Given informationWe have given that out of 67,410 surgeries tracked in a study in the U.K., 2832…

Q: In a study of government financial aid for college students, it becomes necessary to estimate the…

A:

Q: A poll for a statewide election has a margin of error of 3.59 percentage points. How many voters…

A: given data  E = 0.0359 90% ci for p  n = ?

Q: NEWS 21.12 Gun control. A March 2018 Gallup survey asked a sample of 1041 adults if they wanted…

A: From the provided information, Sample size (n) = 1041 From which 697 of the survey respondents said…

Q: how many students do we need to construct a 95% confidence interval for the proportion of the…

A: here given ,  margin of error  = 3% = 0.03  confidence level = 95%  n = 150  p^= 0.68

Q: Sleep apnea: Sleep apnea is a disorder in which there are pauses in breathing during sleep. People…

A: Sample size  n = 433Number of people aged 65 and over had sleep apnea(x) = 107

Q: We take a sample of 218 men and find they have an average commute time of 32 minutes with a standard…

A: Given: a sample of 218 men and find they have an average commute time of 32 minutes with a standard…

Q: assume that a sample is used to estimate population proportion p. find the 95% confidence interval…

A:

Q: A simple random sample of 1000 people age 18 or over is taken in a large town. It turns out that 223…

A: From the provided information, Sample size (n) = 1000 223 people in the sample are newspaper…

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.