A real number s that is irrational is called algebraic if it is the root of a polynomial equation with integer coefficents. For example, s = v2 is alge- braic since it is a root of r2-2 0. Numbers that are irrational but not algebraic are called transcendental. (a) Show that the set of all algebraic numbers is countable. Hint: show that there are countably many polynomials with integer coeffi- cients. You may assume that a polynomial of degree n has n roots. You may also assume class theorems, and that if A is a countable set, then for n > 1, the set of n-tuples of elements of A, A" = {(a1, a2, .., a„) : each a, E A} is also countable. (b) Show that the set of all transcendental numbers is uncountable.

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### Algebraic and Transcendental Numbers

A real number \( s \) that is irrational is called **algebraic** if it is the root of a polynomial equation with integer coefficients. For example, \( s = \sqrt{2} \) is algebraic since it is a root of \( x^2 - 2 = 0 \). Numbers that are irrational but not algebraic are called **transcendental**.

#### Exercises:

**(a) Show that the set of all algebraic numbers is countable.**
- **Hint**: Show that there are countably many polynomials with integer coefficients. You may assume that a polynomial of degree \( n \) has \( n \) roots. You may also assume class theorems, and that if \( A \) is a countable set, then for \( n \geq 1 \), the set of \( n \)-tuples of elements of \( A \), \( A^n = \{ (a_1, a_2, ..., a_n) : \text{each } a_j \in A \} \) is also countable.

**(b) Show that the set of all transcendental numbers is uncountable.**
Transcribed Image Text:### Algebraic and Transcendental Numbers A real number \( s \) that is irrational is called **algebraic** if it is the root of a polynomial equation with integer coefficients. For example, \( s = \sqrt{2} \) is algebraic since it is a root of \( x^2 - 2 = 0 \). Numbers that are irrational but not algebraic are called **transcendental**. #### Exercises: **(a) Show that the set of all algebraic numbers is countable.** - **Hint**: Show that there are countably many polynomials with integer coefficients. You may assume that a polynomial of degree \( n \) has \( n \) roots. You may also assume class theorems, and that if \( A \) is a countable set, then for \( n \geq 1 \), the set of \( n \)-tuples of elements of \( A \), \( A^n = \{ (a_1, a_2, ..., a_n) : \text{each } a_j \in A \} \) is also countable. **(b) Show that the set of all transcendental numbers is uncountable.**
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