A real estate agent believes that the mean home price in the northern part of a county is higher than the me price in the southern part of the county and would like to test the claim. A simple random sample of housing prices is taken from each region. The results are shown below. Southern Northern Mean Variance 154.889 167.833 354.458 521.912 18 18 Observations Pooled Variance 438.185 Hypothesized Mean Difference 0 df 34 t Stat 1.885 p= Ex: 1.234 P(T<=t) one-tail 0.036 t Critical one-tail 1.691 P[T<=t) two-tail 0.072 2.032 -3 -2 -1 1 2 t Critical two-tail Confidence Level 95% 3 t = Ex: 1.234 n = Ex: 9 Degrees of freedom: df = Point estimate for the southern part of the county: ₁ = Ex: 1.234 Point estimate for the northern part of the county: ₂ = 0
A real estate agent believes that the mean home price in the northern part of a county is higher than the me price in the southern part of the county and would like to test the claim. A simple random sample of housing prices is taken from each region. The results are shown below. Southern Northern Mean Variance 154.889 167.833 354.458 521.912 18 18 Observations Pooled Variance 438.185 Hypothesized Mean Difference 0 df 34 t Stat 1.885 p= Ex: 1.234 P(T<=t) one-tail 0.036 t Critical one-tail 1.691 P[T<=t) two-tail 0.072 2.032 -3 -2 -1 1 2 t Critical two-tail Confidence Level 95% 3 t = Ex: 1.234 n = Ex: 9 Degrees of freedom: df = Point estimate for the southern part of the county: ₁ = Ex: 1.234 Point estimate for the northern part of the county: ₂ = 0
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Question
Transcribed Image Text:402562 2600368.qx3zqy7
Start
A real estate agent believes that the mean home price in the northern part of a county is higher than the mean
price in the southern part of the county and would like to test the claim. A simple random sample of housing
prices is taken from each region. The results are shown below.
Mean
Southern Northern
154.889 167.833
354.458 521.912
Variance
Observations
Pooled Variance
438.185
0
Hypothesized Mean Difference
t Stat
1.885
P= Ex: 1.234
PIT<-t) one-tail
0.036
t Critical one-tail
1.691
P(T<=t) two-tail
0.072
t Critical two-tail
2.032
2
-1
1
2
Confidence Level
95%
t = Ex: 1.234
n= Ex: 9
Degrees of freedom: df
Point estimate for the southern part of the county: 1
Ex: 1.234
Point estimate for the northern part of the county: ₂ =
J.
3
10
@
05
(CC
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