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(a) Rank the following functions in increasing order of growth; that is, if function fn) is immediately before function g(n) in your list, then it should be the case that fn) is O(g(n)). g2(n) = E7 lg Ig(n – i) gs(n) = 10'e(1glg n)!)/lg lg n gs(n) = 2" g1(n) = Egn-1lg ]g g3(n) = (lg n)! Li=1 i%3D1 8:(n) = 21g lg lg n g7(n) = n 86(1)= lg((lg n)!) 3 To simpnlify notations wzO write fln) s< alr) to mean flu) = olgln)) and flu) = alx)

(a) Rank the following functions in increasing order of growth; that is, if function fn) is immediately before function g(n) in your list, then it should be the case that fn) is O(g(n)). g2(n) = E7 lg Ig(n – i) gs(n) = 10'e(1glg n)!)/lg lg n gs(n) = 2" g1(n) = Egn-1lg ]g g3(n) = (lg n)! Li=1 i%3D1 8:(n) = 21g lg lg n g7(n) = n 86(1)= lg((lg n)!) 3 To simpnlify notations wzO write fln) s< alr) to mean flu) = olgln)) and flu) = alx)

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Please refer to the attached image. Please show how the function can be simplified if possible, thank you.

(a) Rank the following functions in increasing order of growth; that is, if function fn) is immediately before function g(n) in your list, then it should be the case that fn) is O(g(n)). g1(n) = E- lg lg" 82(n) = E7 lg Ig(n – i) gs(n) = 10!g(1g lg n)!)/lg lg n g8(n) = 2" g3(n) = (lg n)! %3D Li=1 i%3D1 84(n) = 2\g lg lg n 87(n) = n³ 86(n)= lg((lg n)!) 3 To simplify notations, we write f(n) << g(n) to mean f(n) = o(g(n)) and f(n) = g(n) to mean f(n) = 0(g(n)). For example, the four functions n², n, (2013n² + n) and n could be sorted in increasing order of growth as follows: ( n << n² = (2013n²+ n) < n³ ).
Transcribed Image Text:(a) Rank the following functions in increasing order of growth; that is, if function fn) is immediately before function g(n) in your list, then it should be the case that fn) is O(g(n)). g1(n) = E- lg lg" 82(n) = E7 lg Ig(n – i) gs(n) = 10!g(1g lg n)!)/lg lg n g8(n) = 2" g3(n) = (lg n)! %3D Li=1 i%3D1 84(n) = 2\g lg lg n 87(n) = n³ 86(n)= lg((lg n)!) 3 To simplify notations, we write f(n) << g(n) to mean f(n) = o(g(n)) and f(n) = g(n) to mean f(n) = 0(g(n)). For example, the four functions n², n, (2013n² + n) and n could be sorted in increasing order of growth as follows: ( n << n² = (2013n²+ n) < n³ ).
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