A random sample of 84 students at a university showed an average age of 22 years and a sample standard deviation of 3 years. Find the margin of error for the 94% confidence interval. (Assume that the population of students is large relative to the sample size. Round your solution to 4 decimal places

Q: A random sample of 20 students yielded a mean of 68,55 and a standard deviation of 4,59 for scores…

A: The question is about confidence interval Given : Randomly selected no. of students ( n ) = 20…

Q: test. It was found that 80 of them scored higher than 100. Based on this, compute a 95% confidence…

A: According to the given information in this question We need to construct 95% confidence interval

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Q: A psychiatrist is interested in finding a 95% confidence interval for the tics per hour exhibited by…

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Q: You measure 50 dogs' weights, and find they have a mean weight of 30 ounces. Assume the population…

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Q: A poll of n = 500 randomly selected elementary school students resulted in 110 of them stating…

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Q: A random sample of 59 four-year-olds attending daycare centers provided a yearly tuition average of…

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Q: You measure 40 turtles' weights, and find they have a mean weight of 42 ounces. Assume the…

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Q: maximal margin of error associated with a 90% confidence interval for the true population mean…

A: You measure 45 watermelon's weights, and find they have mean weight of 68 ounces.  population…

Q: An important factor in selling a residential property is the number of people who look through the…

A: Since the sample size is small and population standard deviation is unknown, t distribution can be…

Q: A recent survey of 6 social networking sites has a mean of 15.9 million visitors for a specific…

A: Given Data: Sample mean (x )=15.9 Standard deviation (sd)=3.3 n=6   We know that x-μsd/n~ tn-1

Q: A poll of n = 500 randomly selected elementary school students resulted in 110 of them stating…

A:

Q: A research scientist wants to know how many times per hour a certain strand of bacteria reproduces.…

A:

Q: A random sample of fifty-six 200-meter swims has a mean time of 3.86 minutes and the population…

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Q: Find the 95% confidence interval for the standard deviation of the ages of residents in a senior…

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Q: Find the 95% confidence interval for the standard deviation of the ages of residents in a senior…

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Q: A research scholar wants to know how many times per hour a certain strand of virus reproduces. The…

A: It is given that,Sample mean = 11.3.Population standard deviation, sigma is 2.3.The sample size, n…

Q: Assume that population mean is to be estimated from the sample described. Use the sample results to…

A: Given95% confidence interval N=361 x = 59.1 seconds. z= 4.9 SecondsFind the margin of error?

Q: Remember the formula for the 80% confidence interval of a single proportion(see picture) : what is…

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Q: A sample of 10 adult elephants had an average weight of 12,881 pounds. The standard deviation for…

A: Given,sample size(n)=10sample mean(x)=12881standard deviation(s)=27degrees of…

Q: You measure 40 turtles' weights, and find they have a mean weight of 71 ounces. Assume the…

A: From the Standard Normal Table, the z value for 90% level is 1.645.

Q: A group of 65 randomly selected students have a mean score of 30.6 with a standard deviation of 5.4…

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Q: vey of 9 social networking sites has a mean of 13.74 million visitors for a specific month. The…

A: As the population standard deviation is not known, we will use t distribution.Degrees of freedom are…

Q: Overweight Men For a random sample of 70 overweight men, the mean of the number of pounds that they…

A: The sample size is 70, the sample mean is 29 and the population standard deviation is 4.3.

Q: In a random sample of 500 Americans, 50% indicated that they have a cat for a pet. Estimate with 95%…

A: Given information

Q: A random sample of 43 cars in the drive-thru of a popular fast food restaurant revealed an average…

A: Given that mean=16.87

Q: Find a 90% confidence interval for the population mean age of the Smurfs if a sample of 52 smurfs…

A: It is given that, There is a random sample of size 52 and has a mean of 49.7 and the standard…

Q: It took an average of 4.4 years for a grove of 57 orange trees to bear fruit. Assume the standard…

A: Solution-: Given: x¯=4.4,n=57,σ=3.7,α=0.04 We find 96% C.I. =?

Q: A random sample of 43 cars in the drive-thru of a popular fast-food restaurant revealed an average…

A: given data n = 43x¯ = 19.65σ = 5.7696% ci for μ = ?

Q: A sample of 1100 observations taken from a population produced a sample proportion of 0.36 . Make a…

A: Given information Sample proportion = 0.36 Sample size (n) = 1100

Q: You measure 50 turtles' weights, and find they have a mean weight of 76 ounces. Assume the…

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Q: A random sample of 49 drivers used on average 753 gallons of gasoline per year. The standard…

A: Introduction: The 100 (1 – α) % confidence interval for the population mean, μ, when the population…

Q: You have a random sample of 30 mice, the mean of the number of pounds that they were eating was 5…

A: A confidence interval is a type of estimate computed from the statistics of the observed data. This…

Q: Which one of the following statements about confidence intervals is false?   Given the same sample…

A: In this case, we need to identify the false statement for confidence interval.

Q: You measure 49 dogs' weights, and find they have a mean weight of 72 ounces. Assume the population…

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Q: Peggy constructed the 95 percent confidence interval (4.8,5.2)(4.8,5.2) to estimate the slope of a…

A: If an interval is introduced as an estimate of the unknown parameter, then it is interval…

Q: You measure 39 turtles' weights, and find they have a mean weight of 48 ounces. Assume the…

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Q: You measure 50 turtles' weights, and find they have a mean weight of 60 ounces. Assume the…

A: Since we know population standard deviation, use z-distribution to find z-critical value. Find…

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.