A randomly selected car salesman's annual salary (in thousands) can be estimated by a random variable that follows X²-distribution with 36 degrees of freedom. Let X be the salary of a randomly selected car salesman. 1. Describe the distribution of X: P(X<50.5)=0.94 P(X<46.2) X<57.1 2. Use the random variable notation to express symbolically each of the following: P(X<50.5)=0.94 P(X<46.2) X<57.1 P(X<50.5)=0.94 P(X<46.2) X<57.1 ii. more than 46.2: iv. more than 126.7: v. less than 150.9: X-Select an answer (df= Select an answer The probability of an event in which the salary of a randomly selected car salesman is less than 50.5 is equal to 0.94. An event in which the salary of a randomly selected car salesman is less than 57.1. 3. Use technology to find the probability that the salary of a randomly selected car salesman is: i. less than 57.1: iii. between 36.4 and 50.9: T N B The probability of an event in which the salary of a randomly selected car salesman is less than 46.2. 4. Find the 91-th percentile: 191% = (round the answer to 2 decimal places) (round the answer to 2 decimal places) (round the answer to 2 decimal places) (round the answer to 2 decimal places) (round the answer to 2 decimal places) (round the answer to 2 decimal places)