A randomly selected car salesman's annual salary (in thousands) can be estimated by a random variable that follows X²-distribution with 36 degrees of freedom. Let X be the salary of a randomly selected car salesman. 1. Describe the distribution of X: P(X<50.5)=0.94 P(X<46.2) X<57.1 2. Use the random variable notation to express symbolically each of the following: P(X<50.5)=0.94 P(X<46.2) X<57.1 P(X<50.5)=0.94 P(X<46.2) X<57.1 ii. more than 46.2: iv. more than 126.7: v. less than 150.9: X-Select an answer (df= Select an answer The probability of an event in which the salary of a randomly selected car salesman is less than 50.5 is equal to 0.94. An event in which the salary of a randomly selected car salesman is less than 57.1. 3. Use technology to find the probability that the salary of a randomly selected car salesman is: i. less than 57.1: iii. between 36.4 and 50.9: T N B The probability of an event in which the salary of a randomly selected car salesman is less than 46.2. 4. Find the 91-th percentile: 191% = (round the answer to 2 decimal places) (round the answer to 2 decimal places) (round the answer to 2 decimal places) (round the answer to 2 decimal places) (round the answer to 2 decimal places) (round the answer to 2 decimal places)
A randomly selected car salesman's annual salary (in thousands) can be estimated by a random variable that follows X²-distribution with 36 degrees of freedom. Let X be the salary of a randomly selected car salesman. 1. Describe the distribution of X: P(X<50.5)=0.94 P(X<46.2) X<57.1 2. Use the random variable notation to express symbolically each of the following: P(X<50.5)=0.94 P(X<46.2) X<57.1 P(X<50.5)=0.94 P(X<46.2) X<57.1 ii. more than 46.2: iv. more than 126.7: v. less than 150.9: X-Select an answer (df= Select an answer The probability of an event in which the salary of a randomly selected car salesman is less than 50.5 is equal to 0.94. An event in which the salary of a randomly selected car salesman is less than 57.1. 3. Use technology to find the probability that the salary of a randomly selected car salesman is: i. less than 57.1: iii. between 36.4 and 50.9: T N B The probability of an event in which the salary of a randomly selected car salesman is less than 46.2. 4. Find the 91-th percentile: 191% = (round the answer to 2 decimal places) (round the answer to 2 decimal places) (round the answer to 2 decimal places) (round the answer to 2 decimal places) (round the answer to 2 decimal places) (round the answer to 2 decimal places)
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:Question 24
A randomly selected car salesman's annual salary (in thousands) can be estimated by a random variable
that follows X²-distribution with 36 degrees of freedom. Let X be the salary of a randomly selected car
salesman.
1. Describe the distribution of X:
P(X<50.5)=0.94
P(X<46.2)
X<57.1
P(X<50.5)=0.94
P(X<46.2)
X<57.1
2. Use the random variable notation to express symbolically each of the following:
P(X<50.5)=0.94
P(X<46.2)
X<57.1
ii. more than 46.2:
iv. more than 126.7:
v. less than 150.9:
X-Select an answer (df=
Select an answer
iii. between 36.4 and 50.9:
T
N
The probability of an event in which the salary of a randomly selected car
salesman is less than 50.5 is equal to 0.94.
An event in which the salary of a randomly selected car salesman is less than
57.1.
3. Use technology to find the probability that the salary of a randomly selected car salesman is:
i. less than 57.1:
U
Z
X²
The probability of an event in which the salary of a randomly selected car
salesman is less than 46.2.
4. Find the 91-th percentile:
191% =
(round the answer to 2 decimal places)
(round the answer to 2 decimal places)
(round the answer to 2 decimal places)
(round the answer to 2 decimal places)
(round the answer to 2 decimal places)
(round the answer to 2 decimal places)
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