A random survey of 540 students was conducted from a population of 2,300 students to estimate the proportion who had part-time jobs. The sample showed that 243 had part-time jobs. Calculate the 95 percent confidence interval for the true proportion of students who had part-time jobs. (Round your answers to 3 decimal places.) The 95% confidence interval is from ______________

Q: Out of a sample of 600 adults aged 18 to 30, 162 still lived with their parents. Based on this,…

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Q: A confidence interval for the true proportional difference between the amount of seniors that have…

A: Ha: P1- P2= 0 H0:P1-P2 not equal to zero

Q: A psychiatrist is interested in finding a 95% confidence interval for the tics per hour exhibited by…

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Q: Out of 100 people sampled, 56 had kids. Based on this, construct a 99% confidence interval for the…

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Q: Calculate the​ 95% confidence intervals for the proportion of children​ surviving, and the…

A: Given information: Count = 711 Adult/Child Frequency Relative Frequency Adult 654 0.91983122…

Q: Out of 300 people sampled, 276 had kids. Based on this, construct a 95% confidence interval for the…

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Q: Out of 600 people sampled, 402 had kids. Based on this, construct a 90% confidence interval for the…

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Q: Out of 300 people sampled, 45 had kids. Based on this, construct a 90% confidence interval for the…

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Q: Suppose a randomly selected sample of n = 54 men has a mean foot length of x = 25.5 cm, and the…

A: Given

Q: If n=380 and X = 304, construct a 90% confidence interval. Give your answers to three decimals…

A: Given,n=380 ,x=304p^=xnp^=304380=0.81-p^=1-0.8=0.2α=1-0.90=0.1α2=0.05Z0.05=1.645     (from Z-table)

Q: A random sample of 1700 workers in a particular city found 646 workers who had full health insurance…

A: Given, The sample proportion is, Critical value: Using z-table, the z-critical value at the given…

Q: The foot lengths of a random sample of 53 men had a mean of 27 cm and a standard deviation of 2 cm,…

A: Solution-:   Given: n1=53 (men), n2=100 (women), x1¯=27, x2¯=23.5, s1=2, s2=2, α=0.05 We want to…

Q: We wish to estimate what percent of adult residents in a certain county are parents. Out of 300…

A: It is given that, out of 300 adult residents sampled, 102 had kids. Thus,  the proportion of the…

Q: In a survey, 30 people were asked how much they spent on their child's last birthday gift. The…

A:

Q: calculate a 95% confidence interval for the population mean body temperature, based on the sample…

A: Given Information: Sample size n=130 Sample mean x¯=98.249 Sample standard deviation s=0.733

Q: Goofy Marketing Solutions conducted a survey among 16 randomly selected visitors to the newly opened…

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Q: A statistics practitioner took a random sample of 56 observations from a population whose standard…

A: We have given that,  Sample size (n) = 56, population standard deviation (σ) = 35 and sample mean…

Q: In a survey, 20 people were asked how much they spent on their child's last birthday gift. The…

A: Givensample size(n)=20mean(x¯)=46standard deviation(s)=10α=1-0.99=0.01α2=0.005Degrees of…

Q: A survey of 90 community members was conducted to measure if community members favored opening a new…

A: It is given that sample size (n) is 90 and x is 68.

Q: If n = 570 and X = 456, construct a 90% confidence interval for the population proportion, p.Give…

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Q: A confidence interval for (u, -µ2) is (-8, 2). Which o

A: The confidence interval for μ1-μ2 is (-8,2)

Q: Out of 100 people sampled, 59 had kids. Based on this, construct a 90% confidence interval for the…

A: We have given that,  Favorable cases (X) = 59 and sample size (n) = 100 Then,  We will find the 90%…

Q: one with a 95% confidence level and the other with a 99.7% confidence level. Which interval is…

A: Confidence interval is probability, which refers that population parameter will fall within set of…

Q: 2011, the U.S. Department of Transportation reported with 95% confidence that the average length of…

A: Given data, x=9.72 E=0.22

Q: Out of 300 people sampled, 42 had kids. Based on this, construct a 95% confidence interval for the…

A: Given: n = 300  X = 42  Confidence level = 95% Formula Used: Confidence Interval = p ± Z*p(1-p)n

Q: In a survey, 10 people were asked how much they spent on their child's last birthday gift. The…

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Q: In a sample of 320 adults, 288 had children. Construct a 95% confidence interval for the true…

A: Here, the number of adults had children, x is 288 and the sample size, n  is 320. The known values…

Q: atistics practitioner took a random sample of 49 observations from a population whose standard…

A: Sample size n =49 Sample mean=103 Population standard deviation =25

Q: Out of 200 people sampled, 140 had kids. Based on this, construct a 90% confidence interval for the…

A: Given data,n=200x=140p=xn=140200=0.70z-value at 90% confidence is Zc=1.645

Q: Suppose a new treatment for a certain disease is given to a sample of 210 patients. The treatment…

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Q: Out of 600 people sampled, 534 had kids. Based on this, construct a 95% confidence interval for the…

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Q: Out of 200 people sampled, 36 had kids. Based on this, construct a 99% confidence interval for the…

A: Givenx=36n=200p^=xn=36200=0.18Confidence Interval(c)=99%α=1-0.99=0.01α2=0.005Critical…

Q: Out of 600 people sampled, 456 had kids. Based on this, construct a 95% confidence interval for the…

A: According to the given information, we have Total number of people sampled = 600 Out of 600 people…

Q: According to data from Cosmopolitan magazine, 64% of Americans say there is never enough time in the…

A: From the given information, According to data from Cosmopolitan magazine, 64% of Americans say there…

Q: Out of 200 people sampled, 122 had kids. Based on this, construct a 90% confidence interval for the…

A: Given that, n = 200 x = 122

Q: A third student polled her class and wrote down the numbers from her data below population standard…

A: 6)  to find the 80% confidence interval of the mean mean = ∑xn=5723=2.48 standard deviation = 2.1

Q: We wish to estimate what percent of adult residents in a certain county are parents. Out of 600…

A:

Q: Out of 600 people sampled, 30 had children under the age of 18. Based on this, construct a 99%…

A:

Q: Which one of the following statements about confidence intervals is false?   Given the same sample…

A: In this case, we need to identify the false statement for confidence interval.

Q: xpress the confidence interval (65.2%,83.2%) in the form of ˆp ± ME. _____% ± _____ %

A: The confidence interval is (65.2%, 83.2%).

Q: ou are interested in constructing a 95% confidence interval for the proportion of all caterpillars…

A: Solution: Given information: n= 409 Sample size of caterpillars  x= 58  caterpillars become…