A random sample of n1 = 10 regions in New England gave the following violent crime rates (per million population). 3.3 3.9 4.2 4.1 3.3 4.1 1.8 4.8 2.9 3.1 Another random sample of n2 = 12 regions in the Rocky Mountain states gave the following violent crime rates (per million population). 3.9 4.1 4.5 5.5 3.3 4.8 3.5 2.4 3.1 3.5 5.2 2.8   Assume that the crime rate distribution is approximately normal in both regions. (a) Use a calculator to calculate x1, s1, x2, and s2. (Round your answers to four decimal places.) x1=s1=x2=s2=

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A random sample of n1 = 10 regions in New England gave the following violent crime rates (per million population).
3.3 3.9 4.2 4.1 3.3 4.1 1.8 4.8 2.9 3.1
Another random sample of n2 = 12 regions in the Rocky Mountain states gave the following violent crime rates (per million population).
3.9 4.1 4.5 5.5 3.3 4.8 3.5 2.4 3.1 3.5 5.2 2.8
 
Assume that the crime rate distribution is approximately normal in both regions.
(a)
Use a calculator to calculate x1s1, x2, and s2. (Round your answers to four decimal places.)
x1=s1=x2=s2=
(b)
Do the data indicate that the violent crime rate in the Rocky Mountain region is higher than in New England? Use ? = 0.01.
(i)
What is the level of significance?
 
State the null and alternate hypotheses.
H0: ?1 = ?2H1: ?1 ≠ ?2H0: ?1 < ?2H1: ?1 = ?2    H0: ?1 = ?2H1: ?1 > ?2H0: ?1 = ?2H1: ?1 < ?2
(ii)
What sampling distribution will you use? What assumptions are you making?
The standard normal. We assume that both population distributions are approximately normal with unknown standard deviations.The Student's t. We assume that both population distributions are approximately normal with unknown standard deviations.    The Student's t. We assume that both population distributions are approximately normal with known standard deviations.The standard normal. We assume that both population distributions are approximately normal with known standard deviations.
What is the value of the sample test statistic? (Test the difference ?1 − ?2. Round your answer to three decimal places.)
 
(iii)
Find (or estimate) the P-value.
P-value > 0.2500.125 < P-value < 0.250    0.050 < P-value < 0.1250.025 < P-value < 0.0500.005 < P-value < 0.025P-value < 0.005
 
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