A random sample of 17 adult male wolves from the Canadian Northwest Territories gave an average weight x1 = 98.6 pounds with estimated sample standard deviation s1 = 5.6 pounds. Another sample of 26 adult male wolves from Alaska gave an average weight x2 = 88.2 pounds with estimated sample standard deviation s2 = 6.0 pounds. (a) Categorize the problem below according to parameter being estimated, proportion p, mean μ, difference of means μ1 – μ2, or difference of proportions p1 – p2. Then solve the problem. μp μ1 – μ2p1 – p2 (b) Let μ1 represent the population mean weight of adult male wolves from the Northwest Territories, and let μ2 represent the population mean weight of adult male wolves from Alaska. Find a 99% confidence interval for μ1 – μ2. (Use 1 decimal place.) lower limit upper limit (c) Examine the confidence interval and explain what it means in the context of this problem. Does the interval consist of numbers that are all positive? all negative? of different signs? At the 99% level of confidence, does it appear that the average weight of adult male wolves from the Northwest Territories is greater than that of the Alaska wolves? Because the interval contains only positive numbers, we can say that Canadian wolves weigh more than Alaskan wolves.Because the interval contains both positive and negative numbers, we can not say that Canadian wolves weigh more than Alaskan wolves. We can not make any conclusions using this confidence interval.Because the interval contains only negative numbers, we can say that Alaskan wolves weigh more than Canadian wolves.

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A random sample of 17 adult male wolves from the Canadian Northwest Territories gave an average weight x₁ = 98.6 pounds with estimated sample standard deviation s₁ = 5.6 pounds. Another sample of 26 adult male wolves from Alaska gave an average weight x₂ = 88.2 pounds with estimated sample standard deviation s₂ = 6.0 pounds.

(a) Categorize the problem below according to parameter being estimated, proportion p, mean μ, difference of means μ₁ – μ₂, or difference of proportions p₁ – p₂. Then solve the problem.

μp μ₁ – μ₂p₁ – p₂

(b) Let μ₁ represent the population mean weight of adult male wolves from the Northwest Territories, and let μ₂ represent the population mean weight of adult male wolves from Alaska. Find a 99% confidence interval for μ₁ – μ₂. (Use 1 decimal place.)

lower limit
upper limit

(c) Examine the confidence interval and explain what it means in the context of this problem. Does the interval consist of numbers that are all positive? all negative? of different signs? At the 99% level of confidence, does it appear that the average weight of adult male wolves from the Northwest Territories is greater than that of the Alaska wolves?

Because the interval contains only positive numbers, we can say that Canadian wolves weigh more than Alaskan wolves.Because the interval contains both positive and negative numbers, we can not say that Canadian wolves weigh more than Alaskan wolves. We can not make any conclusions using this confidence interval.Because the interval contains only negative numbers, we can say that Alaskan wolves weigh more than Canadian wolves.

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