A random sample of monthly internet usage bills from three different telecommunicationproviders were collected among the university students at College H. The result as follow.ANOVAInternet UsageSum of SquaresdfMean SquareFSig.Between Groups1613.771R.069Within GroupsP12238.773Total4479.04214a) What are the TWO (2) main assumptions for the model above?b) Compute the values of P, Q, R and s.c) Using p-value approach, is there any evidence to indicate the mean internet usage billsamong the university students are different from the three telecommunication providers?Use a=0.05.

We need to answer given questions based on concept of ANOVA.

Answered: A random sample of monthly internet…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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During the COVID-19 pandemic, drive-up grocery delivery became very popular with customers. Two US retailers that provide this service are Target and Walmart. Many shoppers prefer to order from only one store to save time, but they wonder if they are spending more money shopping at one store rather than both. The data file Snacks has the prices for 20 identical snack items sold at both retailers in Mankato, Minnesota. Assume that µd is the mean difference (Target - Walmart) in the price of the items. Using α = .05, determine whether or not the price of these grocery items differed significantly. Perform your analysis using MegaStat. Download: Snacks a. What type of analysis should you use to analyze this data? Explain the reason for your choice. b. State the hypotheses for this analysis. c. Calculate the degrees of freedom for this analysis. d. State the Decision Rule for this analysis. e. Perform the analysis and identify the mean price of the Target items, the mean price of the…
In order to be able to statistically determine which levels of the significant main effect(s) differ dec the analysis of variance, which of the following is performed? A)t-test B)Simple linear regression analysis C)Post-hoc analysis D)Analysis of residues
A study was conducted to examine the difference between the average cholesterol levels in the blood of men and females. It can be assumed that cholesterol levels follow a normal distribution in both populations and that the distribution in the populations is similar (e. Assume that cholesterol levels follow a normal distribution in both populations with similar variances). An equal number of measurements were made on men and women. The results were entered into R and the R code and output can be seen below: t.test(kol$mael-kol$kyn,var.equal = T) %3D Two Sample t-test data: kol$mael by kol$kyn t = 5.7731, df = 18, p-value alternative hypothesis: true difference in means is not equal to 0 95 percent confidence interval: 15.28775 32.78050 = 0.000018 sample estimates: mean in group Men mean in group women 219.2115 195.1774 1. Which statement is best based on the results of the study? Use a=0.05. a. The P-value is lower than a and therefore can be rejected HO b. The P-value is higher than a…
What is the odds ratio for a study with a logistic regression coefficient of -0.2524? a) 0.78 b) 1.00 c) -0.78 d) -2524
Suppose a data set from a bike share company contains the number of daily bike rentals at each of 6 stations for the 23 weekdays of a particular month, i.e. we have Yij for i = 1, ..., 23 and j 1,...6. Write down a hierarchical normal model that can be used to estimate the mean number of bike rentals at each station. You can assume that the unknown variance o? of the number of bike rentals is the same for each station.
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1. A study compared the number of tree species in unlogged forest plots to similar plots logged 8 years earlier. Independent random samples of both logged and unlogged plots were analyzed and the number of tree species was recorded. Tables 1 and 2 present the Shapiro-Wilk normality test for both types of forest plots and the Independent Samples t-test results. Use the information presented in these tables to answer the questions. Table 1: Tests of Normality Tests of Normality Kolmogorov-Smirnov Shapiro-Wilk Forest Plot Statistic df Sig. Statistic df Sig. Tree_Species Logged .181 12 .200 .936 12 .444 Unlogged .110 14 .200 .945 14 .480 *. This is a lower bound of the true significance. a. Lilliefors Significance Correction Table 2: Independent Samples Test Independent Samples Test Levene's Test for Equality of Variances t-test for Equality of Means 95% Confidence Interval of the Difference Mean Std. Error F Sig. t df Sig. (2-tailed) Difference Difference Lower Upper Equal variances…
To determine the average length of hospital stay for patients who were hospitalized with and recovered from Covid-19, a physician randomly surveyed 100 of his patients and determined their average length of hospital stay. Identify the population, parameter, sample, and statistic for the above scenario. Write "NONE" for any information that is missing.
12.21 In the study of Exercise 12.9, 25 observations were used to calculate the least squares estimates. The regression sum of squares and error sum of squares were found to be as follows: SSR 79.2 and SSE = 45.9 = a. Find and interpret the coefficient of determination. b. Find the adjusted coefficient of determination. c. Find and interpret the coefficient of multiple correlation.
2
The total expenses of a hospital (dependent variable) are related to many factors. One of these factors is the number of admissions to the hospital (independent variable). Using the summary output below to answer, what is the meaning (analysis) of the coefficient of determination? SUMMARY OUTPUT Multiple R R Square Adjusted R Square Standard Error Observations ANOVA Regression Statistics Regression Residual Total df 0.98706 0.974288 0.972145 8.106794 Coefficients 14 1 12 13 SS 29883.07 788.6412 30671.71 Standard Error Intercept 1.518053 Admissions 0.668591 OA) is the value of Expenses with one unit increase in Admissions 3.248929 0.031354 MS 29883.07 65.7201 t Stat 0.467247 21.32375 F 454.7022 P-value 0.648693 6.59E-11 Significance F 6.59E-11 Lower 95% -5.56075 0.600276 Upper 95% 8.59686 0.736907

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