A random sample of 64 SAT scores of students applying for merit scholarships showed an average of 1200 with a standard deviation of 200. Find the t value needed to develop the 95% confidence interval for the population mean SAT score. O 1.645 O 1.669 O 1.96 O 1.998

Q: A researcher wants to estimate the mean blood cholesterol level of young men ages 15-25 with a…

A: Given that,  Confidence interval =83.56% Standard deviation=35 mg/dl We have to find the value of n

Q: Salaries of 39 college graduates who took a statistics course in college have a​ mean, x of $63,300.…

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Q: One measure of physical fitness is the amount of time it takes for the pulse rate to return to…

A: Confidence interval for population mean: Confidence interval for population mean is the range of…

Q: A student reported a 95% confidence interval of [3.21,4.29] What is the mean of the data set?…

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Q: A sample of 25 bottles of orange juice were measured and the sample standard deviation is 1.8…

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Q: A random sample of 75 sales employees work an average of ?̅ = 40 hours per week in a company. Assume…

A: Given information Sample size, n = 75 Sample mean, x-bar = 40 hours Population standard deviation, σ…

Q: Find a 90% confidence interval for the population standard deviation if you are given a sample of 10…

A: Given data : sample size,n = 10 df=n-1= 9 sample standard deviation,s= 3.0…

Q: Four hundred randomly selected working adults in a certain state, including those who worked at…

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Q: Calculate a 95% upper confidence bound for the mean of a normally distributed population using the…

A: given data  x¯ = 39316n = 14σ= 3276normal distribution 95% upper confidence bound = ?

Q: Suppose a sample of 30 Statistics students are given an IQ test. If the sample has a standard…

A: Given n=30, sample standard deviations s=12.23

Q: Among those taking the Graduate Record Exam, 18 people are randomly selected. This group had a mean…

A: n = 18 s =140 mu = 550

Q: In a random sample of six people, the mean driving distance to work was 24.9 miles and the standard…

A: The sample size: n=6 Sample mean: x¯=24.9 miles Standard deviation: s=7.9 Confidence level: C=0.99…

Q: were found to have an average weight of 9.7 ounces with a sample standard deviation is 0.20. Find…

A: As the population standard deviation is not known, we will use t distribution. Degrees of freedom…

Q: A simple random sample of 50 has been collected from a population for which it is known that s =…

A: It is given that sample mean is 230.0 and the standard deviation is 10.0.

Q: The manager of a fleet of automobiles is testing two brands of radial tires and assigns one tire of…

A: Note- Since you have posted multiple questions, as per our guidelines we are supposed to answer only…

Q: The grade point average collected from a random sample of 150 students producing a mean of 2.86.…

A: The population standard deviation σ=0.78 The mean is x=2.86 and the number of samples n=150 The…

Q: It is desired to obtain a 95% confidence interval for the mean time µ= 120 minutes to take the…

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Q: At a college, a popular achievement test is used for advanced college placement. Counselors selected…

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Q: A random sample of fifty-SIx 200-meter swims has a mean time of 3.86 minutes and the population…

A: Given that  Sample size n =56 Sample mean =3.86 Population standard deviation =0.06

Q: A group of 10 foot surgery patients had a mean weight of 240 pounds. The sample standard deviation…

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Q: The average GRE scores of graduated students at a particular university has an unknown mean and…

A: Given,sample size(n)=1000sample mean(x¯)=500satandard deviation(s0=50degrees of…

Q: A statistics teacher taught a large introductory statistics class, with 500 students having enrolled…

A: Given, The null and alternative hypothesis. and population mean and standard deviation. also Sample…

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Q: A study of 96 bolts of carpet showed that their average length was 77.5 yards. The standard…

A: GivenMean(x)=77.5sample size(n)=96standard deviation(s)=1.6α=1-0.99=0.01α2=0.005zα2=z0.05=2.58

Q: Find the 90% confidence interval for the standard deviation of the lengths of pipes if a sample of…

A: given data s = 10.2 n = 22 90% CI for σ = ? α = 1 - 0.90 = 0.10df = n - 1 = 21χ2L = χ21-α2,n-1…

Q: ample mean of 62.2 was found and a 95% confidence interval of (57.3, 67.1) was also found. What is…

A: The sample mean for the  population is 62.2  . Confidence interval is (57.3 , 67.1)

Q: A 95% confidence interval for the mean hours freshmen spent on social media per day was calculated…

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Q: A random sample of 150 students has a grade point average with a mean of 2.86. Assume the population…

A: Given,      sample size n =150      Mean x-=2.86      standard deviation σ=0.78…

Q: Suppose a sample of 25 students with a sample me an IQ of 127. The population standard deviation was…

A: Given. sample size (n) = 25 sample mean (x̄) =127 population standard deviation (σ) = 5.4 a)…

Q: tudy of 40 English professors showed that they spend, on average, 12.6 minutes correcting a…

A: given data,x¯ = 12.6s=2.5CI=.99α=1-0.99=0.01n=40df=n-1=40-1=39we have to find out the confidence…

Q: Which equation is the correct confidence interval to use in this problem? X-to/2, X + ta/2유)…

A: From the provided information, Sample size (n) = 30 Sample standard deviation (s) = 12.23

Q: Create a 85% confidence interval for a population mean from a sample of size 65 with sample mean x =…

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Q: The 95% confidence interval of the variance of a population is computed as (12.367,21.761).…

A: Given information: The 95% confidence interval for the variance of a population is (12.367, 21.761).…