A random sample of 45 colleges was taken. The mean rate of graduation within four years was 65% with a margin of error of 3.88%. The distribution of graduation rates is Normal. a) Based on this, give the confidence interval for the true mean rate of graduation. Give your answers rounded to two decimal places % < µ < b) Can we reject a population mean percentage of 70.88% on the basis of these numbers? Explain. Yes, reject 70.88%. Since 70.88% is not in the interval, it is not possible the population graduation rate is 70.88%. O No, do not reject 70.88%. Since 70.88% is not in the interval, it is possible the population graduation rate is 70.88%. Yes, reject 70.88%. Since 70.88% is in the interval, it is not possible the population graduation rate is 70.88% . O No, do not reject 70.88%. Since 70.88% is in the interval, it is possible the population graduation rate is 70.88%.
A random sample of 45 colleges was taken. The mean rate of graduation within four years was 65% with a margin of error of 3.88%. The distribution of graduation rates is Normal. a) Based on this, give the confidence interval for the true mean rate of graduation. Give your answers rounded to two decimal places % < µ < b) Can we reject a population mean percentage of 70.88% on the basis of these numbers? Explain. Yes, reject 70.88%. Since 70.88% is not in the interval, it is not possible the population graduation rate is 70.88%. O No, do not reject 70.88%. Since 70.88% is not in the interval, it is possible the population graduation rate is 70.88%. Yes, reject 70.88%. Since 70.88% is in the interval, it is not possible the population graduation rate is 70.88% . O No, do not reject 70.88%. Since 70.88% is in the interval, it is possible the population graduation rate is 70.88%.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Step 1 Given that
n= 45
sample mean = 65%
Margin of error = E = 3.88%
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