A random sample of 41 subjects who identified themselves as compulsive buyers was obtained and given a questionnaire. They had a mean questionnaire score of0.55 with a standard deviation of 0.13. Test the claim that the population of self-identified compulsive buyers has mean greater than the mean of 0.53 for thegeneral population. Use a 0.05 significance level.OState the null and alternative hypotheses.OA. Ho: 0.53OB. Ho: μ=0.53H₂: μ = 0.53Hg:μ <0.53OC. Ho: μ = 0.53O D. Ho: μ=0.53H₂:μ>0.53H₂: μ*0.53Find the z-score.Z= (Round to two decimal places as needed.)Find the P-value.The P-value is(Round to four decimal places as needed.)State the conclusion.O A. The P-value is less than or equal to the significance level. There is not sufficient evidence to support the claim that the population of self-identifiedcompulsive buyers has mean greater than the mean of 0.53 for the general population.OB. The P-value is less than or equal to the significance level. There is sufficient evidence to support the claim that the population of self-identified

Given n=41, sample mean x̄=0.55, standard deviations σ=0.13, population mean μ=0.53 Level of…

Answered: A random sample of 41 subjects who…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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If the p-value of a hypothesis test is equal to 0.035, then the null hypothesis will be rejected for which cases? SELECT ALL THAT APPLY. a. for a significance level of 0.01 b. for a significance level of 0.10 c. for a significance level of 0.05 d. for a significance level of 0.02
Test the claim that the mean GPA of night students is significantly different than 3.3 at the 0.2 significance level. The null and alternative hypothesis would be: Ho:p0.825 H p 3.3 H p 0.825 H p <3.3 H:p 3.3 The test is: right-tailed two-tailed left-tailed Based on a sample of 80 people, the sample mean GPA was 3.33 with a standard deviation of 0.04 The p-value is: (to 2 decimals) Based on this we: Reject the null hypothesis Fail to reject the null hypothesis
Find the p-value that corresponds to the given standard score, and determine whether to reject the null hypothesis at the 0.10 significance level. Is the alternative hypothesis supported? Z= 0.9 for H0: u=136 pounds and Ha: u is not = 136 pounds. The p-value is ?
Next Question Assume a significance level of a = 0.05 and use the given information to cd d (b) below. Original claim: More than 43% of adults would erase all of their personal information online if they could. The hypothesis test results in a P-value of 0.0443. ..... a. State a conclusion about the null hypothesis. (Reject Ho or fail to reject Ho.) Choose the correct answer below. A. Fail to reject Ho because the P-value is greater than x. B. Reject H, because the P-value is less than or equal to a. C. Fail to reject H, because the P-value is less than or equal to a. O D. Reject Ho because the P-value is greater than a. b. Without using technical terms, state a final conclusion that addresses the original claim. Which of the following is the correct conclusion? A. There is sufficient evidence to support the claim that the percentage of adults that would erase all of their personal information online if they could is more than 43%. B. There is not sufficient evidence to support the…
In a study of the accuracy of fast food drive-through orders, one restaurant had 40 orders that were not accurate among 321 orders observed. Use a 0.01 significance level to test the claim that the rate of inaccurate orders is equal to 10%. Does the accuracy rate appear to be acceptable? Identify the null and alternative hypotheses for this test. Choose the correct answer below. A. H0: p≠0.1 H1: p=0.1 B. H0: p=0.1 H1: p<0.1 C. H0: p=0.1 H1: p≠0.1 D. H0: p=0.1 H1: p>0.1 Identify the test statistic for this hypothesis test. The test statistic for this hypothesis test is ______ (Round to two decimal places as needed.) Identify the P-value for this hypothesis test. The P-value for this hypothesis test is _______ (Round to three decimal places as needed.) Identify the conclusion for this hypothesis test. A. Reject H0. There is not sufficient evidence to warrant rejection of the claim that the rate of…
The test statistic of z=1.54 is obtained when testing the claim that p=0.723. a. Identify the hypothesis test as being two-tailed, left-tailed, or right-tailed. b. Find the P-value. c. Using a significance level of a=0.10, should we reject H0 or should we fail to reject H0?
In one study of smokers who tried to quit smoking with nicotine path therapy,38 were smoking one year after the treatment, and 32 were not smoking one year after the treatment. Use a 0.10 significance level to test the claim that among smokers who try to quit with nicotine patch therapy, the majority are smoking a year after the treatment. d. Calculate the test statistic z. Which of these options is closest to z? A. negative 2.02 B. 0.72 C. negative 0.25 D. 2.59 e. Calculate the P-value. Which of these options is closest to the P-value? A. 0.2358 B. 0.2164 C. 0.3359 D. 0.2271 f. State the technical conclusion A. Reject Upper H 0 B. Do not reject Upper H 0 g. State the final conclusion A. There is sufficient evidence to warrant rejection of the claim. B. There is not sufficient evidence to warrant rejection of the claim.…
In a study of the accuracy of fast food drive-through orders, one restaurant had 38 orders that were not accurate among 335 orders observed. Use a 0.10 significance level to test the claim that the rate of inaccurate orders is equal to 10%. Does the accuracy rate appear to be acceptable? Identify the null and alternative hypotheses for this test. Choose the correct answer below. Ho:p = 0.1 H4:p#0.1 O B. Ho: p#0.1 H1:p=0.1 OC. Ho: p=0.1 H:p0.1 Identify the test statistic for this hypothesis test. The test statistic for this hypothesis test is 0.82 (Round to two decimal places as needed.) Identify the P-value for this hypothesis test. The P-value for this hypothesis test is (Round to three decimal places as needed.) Enter your answer in the answer box and then click Check Answer. Final Check parts 2 remaining Clear All MacBook Pro 4) トII トト 88 F10 F7 F9 esc F3 F5 F4 F1 F2 @ 2$ % & delete 2 3 4 6. 7 8 Q W E T Y tab F G K A S caps lock くつ DI
You are conducting a hypothesis test on the outcome of an Statistics test at a large state University. Your null hypothesis is that the overall class average is less than or equal to 0.80. You take a sample of 64 people (a large sample), and find that the sample average is 0.82, and the standard deviation is 0.05. Your hypothesis test will be conducted at the 0.01 significance level. You calculate your test statistic would be 3.20. Would your test statistic be higher or lower if, instead, you were testing at the 0.01 level? Group of answer choices Lower HIgher The same (neigher higher, nor lower).
Consider a drug testing company that provides a test for marijuana usage. Among 294 tested subjects, results from 29 subjects were wrong (either a false positive or a false negative). Use a 0.05 significance level to test the claim that less than 10 percent of the test results are wrong. Identify the null and alternative hypotheses for this test. Choose the correct answer below. OA. Ho: p=0.1 H₁: p0.1 OD. Ho: p=0.1 H₁: p=0.1 Identify the test statistic for this hypothesis test. The test statistic for this hypothesis test is. (Round to two decimal places as needed.) Identify the P-value for this hypothesis test. The P-value for this hypothesis test is. (Round to three decimal places as needed.) Identify the conclusion for this hypothesis test.
We have given the value obtained for the test statistic, z, in a one-mean z test. We have also specified whether the test is two tailed, left tailed, or right tailed. Determine the P-value in each case and decide whether, at the 5% significance level, the data provide sufficient evidence to reject the null hypothesis in favor of the alternative hypothesis. a. Right tailed test: z= 2.03 b. Left tailed test: z= -1.84 c. Two-tailed test: z= 3.08 Please also give excel command needed to calculate each of the p-values for each of the questions

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