A random sample of 388 married couples found that 282 had two or more personality preferences in common. In another random sample of 552 married couples, it was found that only 24 had no preferences in common. Let p1 be the population proportion of all married couples who have two or more personality preferences in common. Let p, be the population proportion of all married couples who have no personality preferences in common. (a) Find a 90% confidence interval for p, - p2. (Use 3 decimal places.) lower limit upper limit (b) Explain the meaning of the confidence interval in part (a) in the context of this problem. Does the confidence interval contain all positive, all

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A random sample of 388 married couples found that 282 had two or more personality preferences in common. In another random sample of 552 married
couples, it was found that only 24 had no preferences in common. Let p, be the population proportion of all married couples who have two or more
personality preferences in common. Let p, be the population proportion of all married couples who have no personality preferences in common.
(a) Find a 90% confidence interval for p, - P2. (Use 3 decimal places.)
lower limit
upper limit
(b) Explain the meaning of the confidence interval in part (a) in the context of this problem. Does the confidence interval contain all positive, all
Transcribed Image Text:A random sample of 388 married couples found that 282 had two or more personality preferences in common. In another random sample of 552 married couples, it was found that only 24 had no preferences in common. Let p, be the population proportion of all married couples who have two or more personality preferences in common. Let p, be the population proportion of all married couples who have no personality preferences in common. (a) Find a 90% confidence interval for p, - P2. (Use 3 decimal places.) lower limit upper limit (b) Explain the meaning of the confidence interval in part (a) in the context of this problem. Does the confidence interval contain all positive, all
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