In a random sample of 32 criminals convicted of a certain crime, it was determined that the mean length of sentencing was 63 months, with a standard deviation of 11 months. Construct and interpret a 90% confidence interval for the mean lengthof sentencing for this crime.Click here to view the standard normal distribution table (page 1).Click here to view the standard normal distribution table (page 2).Click here to view the table of critical t-values.Select the correct choice below and fill in the answer boxescomplete your choice.(Use ascending order. Round to one decimal place as needed.)O A. There is a 90% probability that the mean length of sentencing for the crimebetweenandmonths.O B. We can be 90% confident that the mean length of sentencing for the crime is between andmonths.O C. 90% of the sentences for the crime are betweenand months.NextMacBook ProくescG Search or type URLキ&23delete23478.QWETYab11SFH.JKckレビしのつDI

Answered: Image /qna-images/answer/9fd19b28-a533-4c3e-bf9b-75cf8c530b1e.jpg

Answered: a random sample of 32 criminals…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Suppose that a normal distribution has a mean of 57 and a standard deviation of 10.2. Between what x values do the middle 89.75% of the data lie? Provide a screenshot of the online calculator result. Do not round off your answers.
PLEASE USE THE 4 STEP PROCESS USED IN AP STATISTICS. SHOW ALL WORK AND STEPS.
A data set includes 106 body temperatures of healthy adult humans having a mean of 98.9°F and a standard deviation of 0.62°F. Construct a 99% confidence interval estimate of the mean body temperature of all healthy humans. What does the sample suggest about the use of 98.6°F as the mean body temperature? Click here to view at distribution table Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table What is the confidence interval estimate of the population mean u? ***** (Round to three decimal places as needed) What does this suggest about the use of 98.6°F as the mean body temperature? OA. This suggests that the mean body temperature is lower than 98.6°F OB. This suggests that the mean body temperature could very possibly be 98.6°F OC. This suggests that the mean body temperature is higher than 98.6°F
A newspaper article reports that the mean cost for preventative dental care per year is $175 with a standard deviation of $35 (assume that this is the population standard deviation). You want to test whether the mean cost for preventative dental care in your company is different from what was reported in the article. You take a random sample of 250 employees and find the mean cost is $171. Does this signficantly differ from what was reported in the article? Run the appropriate test at α=0.05. Give each of the following to receive full credit: 1) the appropriate null and alternative hypotheses; 2) the appropriate test; 3) the decision rule; 4) the calculation of the test statistic; and 5) your conclusion including a comparison to alpha or the critical value. You MUST show your work to receive full credit. Partial credit is available.
If a set of sample measurements has a mean of 100, a normal distribution, a standard deviation of 2, and control limits of 94 and 106, what percentage of the samples are expected to be between 94 and 106? Explain your answer.
The average time taken for your Internet service provider to remotely resolve a trouble ticket has a Normal distribution with a mean of 4.3 hours and a standard deviation of 3.1 hours. What percent of the time can you expect to wait longer than a full 8-hour business day for a resolution?
A random sample of 100 automobile owners in a region shows that an automobile is driven on average 25,500 kilometers per year with a standard deviation of 3500 kilometers. Assume the distribution of measurements to be approximately normal. Construct a 90% prediction interval for the kilometers traveled annually by an automobile owner in the region. Click here to view page 1 of the standard normal distribution table. of the standard normal distribution table. Click here to view page 2 Click here to view page 1 of the table of critical values of the t-distribution. Click here to view page 2 of the table of critical values of the t-distribution. The prediction interval is < X < (Round to the nearest integer as needed.) -C
The heights of a random sample of 50 college students showed a mean of 181.6 centimeters and a standard deviation of 6.9 centimeters. (a) Construct a 98% confidence interval for the mean height of all college students. (b) What can we assert with 98% confidence about the possible size of our error if we estimate the mean height of all college students to be 181.6 centimeters? Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. Click here to view page 1 of the table of critical values of the t-distribution. Click here to view page 2 of the table of critical values of the t-distribution. ..... (a) The confidence interval is <µ<. (Round to two decimal places as needed.)
A random sample of 12 graduates of a certain secretarial school typed an average of 82.6 words per minute with a standard deviation of 8.1 words per minute. Assuming a normal distribution for the number of words typed per minute, find a 95% confidence interval for the average number of words typed by all graduates of this school. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. Click here to view page 1 of the table of critical values of the t-distribution. Click here to view page 2 of the table of critical values of the t-distribution. The confidence interval is <μ< (Round to two decimal places as needed.)

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