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A random sample of 17 chemists from Washington state shows an average salary of $49093 with a standard deviation of $536. A random sample of 15 chemists from Florida state shows an average salary of $45101 with a standard deviation of $631. A chemist that has worked in both states believes that chemists in Washington make a different amount than chemists in Florida. At a=0.01 is this chemist correct? Let Washington be sample 1 and Florida be sample 2. The correct hypotheses are: O Ho:µ1 < H2 HA: H1 > µ2(claim) Ο H: μι > μ2 HA: H1 < µ2(claim) O Ho:µ1 = µ2 HA: H1 + H2(claim) Since the level of significance is 0.01 the critical value is 2.766 and -2.766 The test statistic is: (round to 3 places) The p-value is: (round to 3 places) The decision can be made to: O reject Ho O do not reject Ho The final conclusion is that: O There is enough evidence to reject the claim that chemists in Washington make a different amount than chemists in Florida. O There is not enough evidence to reject the claim that chemists in Washington make a different amount than chemists in Florida. O There is enough evidence to support the claim that chemists in Washington make a different amount than chemists in Florida. O There is not enough evidence to support the claim that chemists in Washington make a different amount than chemists in Florida.

A random sample of 17 chemists from Washington state shows an average salary of $49093 with a standard deviation of $536. A random sample of 15 chemists from Florida state shows an average salary of $45101 with a standard deviation of $631. A chemist that has worked in both states believes that chemists in Washington make a different amount than chemists in Florida. At a=0.01 is this chemist correct? Let Washington be sample 1 and Florida be sample 2. The correct hypotheses are: O Ho:µ1 < H2 HA: H1 > µ2(claim) Ο H: μι > μ2 HA: H1 < µ2(claim) O Ho:µ1 = µ2 HA: H1 + H2(claim) Since the level of significance is 0.01 the critical value is 2.766 and -2.766 The test statistic is: (round to 3 places) The p-value is: (round to 3 places) The decision can be made to: O reject Ho O do not reject Ho The final conclusion is that: O There is enough evidence to reject the claim that chemists in Washington make a different amount than chemists in Florida. O There is not enough evidence to reject the claim that chemists in Washington make a different amount than chemists in Florida. O There is enough evidence to support the claim that chemists in Washington make a different amount than chemists in Florida. O There is not enough evidence to support the claim that chemists in Washington make a different amount than chemists in Florida.

A First Course in Probability (10th Edition)
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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A random sample of 17 chemists from Washington state shows an average salary of $49,093 with a standard deviation of $536. A random sample of 15 chemists from Florida state shows an average salary of $45,101 with a standard deviation of $631. A chemist that has worked in both states believes that chemists in Washington make a different amount than chemists in Florida. At α = 0.01 is this chemist correct? Let Washington be sample 1 and Florida be sample 2. The correct hypotheses are: - \( H_0: \mu_1 = \mu_2 \) - \( H_A: \mu_1 \neq \mu_2 \) (claim) Since the level of significance is 0.01 the critical value is 2.766 and -2.766. The test statistic is: __________ (round to 3 places) The p-value is: __________ (round to 3 places) The decision can be made to: - \( \circ \) reject \( H_0 \) - \( \circ \) do not reject \( H_0 \) The final conclusion is that: - \( \circ \) There is enough evidence to reject the claim that chemists in Washington make a different amount than chemists in Florida. - \( \circ \) There is not enough evidence to reject the claim that chemists in Washington make a different amount than chemists in Florida. - \( \circ \) There is enough evidence to support the claim that chemists in Washington make a different amount than chemists in Florida. - \( \circ \) There is not enough evidence to support the claim that chemists in Washington make a different amount than chemists in Florida.
Transcribed Image Text:A random sample of 17 chemists from Washington state shows an average salary of $49,093 with a standard deviation of $536. A random sample of 15 chemists from Florida state shows an average salary of $45,101 with a standard deviation of $631. A chemist that has worked in both states believes that chemists in Washington make a different amount than chemists in Florida. At α = 0.01 is this chemist correct? Let Washington be sample 1 and Florida be sample 2. The correct hypotheses are: - \( H_0: \mu_1 = \mu_2 \) - \( H_A: \mu_1 \neq \mu_2 \) (claim) Since the level of significance is 0.01 the critical value is 2.766 and -2.766. The test statistic is: __________ (round to 3 places) The p-value is: __________ (round to 3 places) The decision can be made to: - \( \circ \) reject \( H_0 \) - \( \circ \) do not reject \( H_0 \) The final conclusion is that: - \( \circ \) There is enough evidence to reject the claim that chemists in Washington make a different amount than chemists in Florida. - \( \circ \) There is not enough evidence to reject the claim that chemists in Washington make a different amount than chemists in Florida. - \( \circ \) There is enough evidence to support the claim that chemists in Washington make a different amount than chemists in Florida. - \( \circ \) There is not enough evidence to support the claim that chemists in Washington make a different amount than chemists in Florida.
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