Question 1(Spts)A random sample of 120 students at BAU was taken to estimate the participating to the office hours. Suppose that the population times have a normal distributionwith a mean of 76 minutes and standartd deviation of 22 minutes.What is the standard error of the sample mean based on the given sample data? Use Excel to calculate it. Use two Decimals.Standard Error of the Mean:

Solution-: Given: μ=76,σ=22,n=120 We find the standard error of the sample mean based on the given…

Answered: A random sample of 120 students at BAU…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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This assignment is worth 1 points. The extra point will be added to your overall course grade. For example: if you receive an 88% in the course you can receive up to 1 point giving you a new score of 89%. The following rubric will be used. 0.25 point for drawing the normal distribution curve with the mean value labeled on the curve and the appropriate area shaded. 0.25 point for determining the value of the standard deviation of the sample mean. 0.5 point for finding the correct probability. All work must be shown in order to receive any credit. Please upload your completed assignment here. The length of time taken on the SAT for a group of students is normally distributed with a mean of 2.5 hours and a standard deviation of 0.25 hours. A sample size of n = 60 is drawn randomly from the population. Find the probability that the sample mean is between two hours and three hours.
In a normal distribution, it is found that the mean is 56 and the standard deviation is 5, Find the range values where 95.60% of the data lies.
The time is takes a studen to walk from the dorn to the chemistry lab follows roughly a Normal distrubtion with a mean of 20 minutes and a stardard deviation of 3 minutes. What porportion of students is faster than 15 minutes when walking from the dorm to the chemistry lab?
Use the information to make a normal distribution using the Empirical Rule, label the mean and three standard deviations from the mean.
Because the mean is very sensitive to extreme values, it is not a resistant measure of center. By deleting some low values and high values, the trimmed mean is more resistant. To find the 10% trimmed mean for a data set, first arrange the data in order, then delete the bottom 10% of the values and delete the top 10% of the values, then calculate the mean of the remaining values. Use axial loads (pounds) of aluminum cans listed below for cans that are 0.0111 in. thick. Identify any outliers, then compare the median, mean, 10% trimmed mean, and 20% trimmed mean. 247 261 269 273 275 280 282 282 284 285 285 287 290 292 293 296 296 299 311 507 Identify any outliers. Select the correct choice below and, if necessary, fill in the answer box to complete your choice. OA. The outlier(s) is/are pounds. (Type a whole number. Use a comma to separate answers as needed.) C OB. There are no outliers.
The goal of the one-sample t-test is to: Group of answer choices describe the location of a score within a distribution compare the mean of a sample to the population mean. compare the means of two samples. compare the standard deviation of a sample to the standard deviation of the population.
Please answer it and explain clearly. Also solve it into handwritten form thank you.
For a random sample of 10 men, the mean head circumferences are x-bar = 57.3 cm, and the sample standard deviation is s = 2cm. what is the standard error of the mean?
If we meet these conditions, the sampling distribution of the mean will have a normal shape and ... The mean of the sampling distribution will be u, (i.e., the same as the population mean) and the standard deviation of the sampling distribution will be (that's the population standard deviation divided by the square root of the sample size). In the AP Stats Guy video, he talks about the number of text messages his students send during class. Suppose the average number of text messages his students send during class is u = 30 text messages. If we take samples of say, n = 36 students at a time, we would expect the mean of the sampling distribution we create to be the same as the population mean, 30 text messages. If we can further say that standard deviation of the number of text messages is 12 text messages, by how much would we expect the sample means to vary? (hint, use the formula above) text messages

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