Question 3, 10.4.52 A random sample of 10 students were surveyed on their social activities. The students were asked to state how many times during the previous year they had gone to a movie, sporting event, orparty. The accompanying table shows the responses. Complete parts a through d below.Click the icon to view the data for attending movies, sporting events, and parties.a. Find and interpret a 95% confidence interval for the difference in the mean number of events attended for parties and sporting events. Define the difference as the number of parties minus thenumber of sporting events.The 95% confidence interval is (-2.44, 27.84).(Round to two decimal places as needed.)It can be stated with % confidence that the population mean difference is between the limits of the confidence interval. Because 0attendedto be different for both types of events.(Type a whole number.)in this interval, the mean number of events Frequency of Attending Movies, Sports Events, and Parties nts, and PartiesActivitySports3Student1234568910Movies91121151049129164171118723311PartiesCHANNE2614752827502254

A confidence interval is an interval that contains the unknown population parameter with some predefined probability. For example, a 95% confidence interval for population standard deviation means it is an interval which has a probability of 95% or 0.95 to include the population standard deviation. In other words, if the hypothesized value of the unknown parameter falls within the confidence interval, then then the null hypothesis is accepted at 5% level of significance.A 100(1 – α)% confidence interval for the difference of the population mean is given by, where, n is number of observations, being the sample mean of x and y respectively, sd' is the sample standard deviation of d with divisor (n - 1), tα,n-1 is the tabulated value of t with degrees of freedom n for α level of significance, x and y being the number of parties and the number of sporting events attended by a student respectively. From the given data we have, We are given, Therefore, a 95% confidence interval for the difference in the mean number of events attended for parties and sporting events is Answer: The blank will be filled up with -2.44 and 27.84 respectively. (as the drop down options are not visible, we will write the most probable options) The blanks will be filled up with 95, lies and are not respectively.