A random number generator assigned each pepper to one of two groups. The weights of the peppers in each group, given three randomizations, appear in the tables.First RandomizationGroup AGroup B13.69.212.18.215.911.511.213.89.714.6Second RandomizationGroup AGroup B8.212.113.814.615.913.69.211.29.711.5Third RandomizationGroup AGroup B8.212.19.713.811.513.614.611.215.99.2For each table, calculate the mean weight for each group, xA¯and xB¯, and find the difference of the mean of group A and the mean of group B (xA¯−xB¯).Type the correct answer in each box.After the first randomization, xA¯is , xB¯is , and (xA¯−xB¯) is .After the second randomization, xA¯is , xB¯is , and (xA¯−xB¯) is .After the third randomization, xA¯is , xB¯is , and (xA¯−xB¯) is .

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Answered: A random number generator assigned each…

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018

18th Edition

ISBN:9780079039897

Author:Carter

Publisher:Carter

Chapter10: Statistics

Section10.6: Summarizing Categorical Data

Problem 10CYU

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A random number generator assigned each pepper to one of two groups. The weights of the peppers in each group, given three randomizations, appear in the tables.

First Randomization
Group A	Group B
13.6	9.2
12.1	8.2
15.9	11.5
11.2	13.8
9.7	14.6

Second Randomization
Group A	Group B
8.2	12.1
13.8	14.6
15.9	13.6
9.2	11.2
9.7	11.5

Third Randomization
Group A	Group B
8.2	12.1
9.7	13.8
11.5	13.6
14.6	11.2
15.9	9.2

For each table, calculate the mean weight for each group, xA¯and xB¯, and find the difference of the mean of group A and the mean of group B (xA¯−xB¯).

Type the correct answer in each box.