A radioactive isotope decays at a rate proportional to the amount of the isotope, in other words dAdt=kAdAdt=kA. The general solution to this differential equation is A=CektA=Cekt.The isotope Nobelium-259 has a half-life of 58 minutes.A) Determine the decay constant, k (Use 6 decimal places). B) If there are 7.6 milligrams of the isotope at t = 0, how much will remain after 12 minutes?
A radioactive isotope decays at a rate proportional to the amount of the isotope, in other words dAdt=kAdAdt=kA. The general solution to this differential equation is A=CektA=Cekt.The isotope Nobelium-259 has a half-life of 58 minutes.A) Determine the decay constant, k (Use 6 decimal places). B) If there are 7.6 milligrams of the isotope at t = 0, how much will remain after 12 minutes?
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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A radioactive isotope decays at a rate proportional to the amount of the isotope, in other words dAdt=kAdAdt=kA. The general solution to this differential equation is A=CektA=Cekt.
The isotope Nobelium-259 has a half-life of 58 minutes.
A) Determine the decay constant, k (Use 6 decimal places).
B) If there are 7.6 milligrams of the isotope at t = 0, how much will remain after 12 minutes?
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