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A radio station claims that the amount of advertising per hour of broadcast time has an average of 17 minutes and a standard deviation equal to 2.2 minutes. You listen to the radio station for 1 hour, at a randomly selected time, and carefully observe that the amount of advertising time is equal to 16 minutes. Calculate the z-score for this amount of advertising time. O A. z = -0.45 OB. z=0.81 O C. z= -0.81 OD. z=0.45

A radio station claims that the amount of advertising per hour of broadcast time has an average of 17 minutes and a standard deviation equal to 2.2 minutes. You listen to the radio station for 1 hour, at a randomly selected time, and carefully observe that the amount of advertising time is equal to 16 minutes. Calculate the z-score for this amount of advertising time. O A. z = -0.45 OB. z=0.81 O C. z= -0.81 OD. z=0.45

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter4: Equations Of Linear Functions
Section4.5: Correlation And Causation
Problem 21PFA
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A radio station claims that the amount of advertising per hour of broadcast time has an average of 17 minutes and a standard deviation equal to 2.2 minutes. You listen to the radio station for 1 hour, at a randomly selected time, and carefully observe that the amount of advertising time is equal to 16 minutes. Calculate the z-score for this amount of advertising time. CO OA. Z-0.45 OB. z=0.81 O C. Z-0.81 O D. z = 0.45
Transcribed Image Text:A radio station claims that the amount of advertising per hour of broadcast time has an average of 17 minutes and a standard deviation equal to 2.2 minutes. You listen to the radio station for 1 hour, at a randomly selected time, and carefully observe that the amount of advertising time is equal to 16 minutes. Calculate the z-score for this amount of advertising time. CO OA. Z-0.45 OB. z=0.81 O C. Z-0.81 O D. z = 0.45
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