A race car is turning (cornering) on a flat road, as shown in Figure Q1-1. The speed of the car is 300 kph and the turning radius is 260 m. Having the car parameters as below, answer questions a) and b). m = 890 (kg) (57% of the weight is on the rear axle); Air density = 1.225 (kg/m³); Equivalent aerodynamic lift coefficient for front axle= -0.915 (-); Aerodynamic frontal area= 1.11 (m²); Slip angle of the front tyres= +2.4 (°); Slip angle of rear tyres= +1.2 (°); The steering angle of wheels= -1.9 (°); The efficiency of the drivetrain from the engine to the contact patch of tyres is 100%.

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Question 1:
A race car is turning (cornering) on a flat road, as shown in Figure Q1-1. The
speed of the car is 300 kph and the turning radius is 260 m. Having the car
parameters as below, answer questions a) and b).
●
.
●
●
m = 890 (kg) (57% of the weight is on the rear axle);
Air density = 1.225 (kg/m3);
Equivalent aerodynamic lift coefficient for front axle= -0.915 (-);
Aerodynamic frontal area= 1.11 (m²);
Slip angle of the front tyres= +2.4 (°);
Slip angle of rear tyres= +1.2 (°);
The steering angle of wheels= -1.9 (°);
The efficiency of the drivetrain from the engine to the contact patch of
tyres is 100%.
8=-1.9°-
---R=260 m
α = +2.4°
αR = +1.2°
Figure Q1-1 Motion of the vehicle and the angles
a) Calculate the engine power delivered to tyres to overcome the total
induced drag due to lateral force.
Transcribed Image Text:Question 1: A race car is turning (cornering) on a flat road, as shown in Figure Q1-1. The speed of the car is 300 kph and the turning radius is 260 m. Having the car parameters as below, answer questions a) and b). ● . ● ● m = 890 (kg) (57% of the weight is on the rear axle); Air density = 1.225 (kg/m3); Equivalent aerodynamic lift coefficient for front axle= -0.915 (-); Aerodynamic frontal area= 1.11 (m²); Slip angle of the front tyres= +2.4 (°); Slip angle of rear tyres= +1.2 (°); The steering angle of wheels= -1.9 (°); The efficiency of the drivetrain from the engine to the contact patch of tyres is 100%. 8=-1.9°- ---R=260 m α = +2.4° αR = +1.2° Figure Q1-1 Motion of the vehicle and the angles a) Calculate the engine power delivered to tyres to overcome the total induced drag due to lateral force.
b) The rolling resistance force at the contact patch of tyres is calculated as
FRR = (fo+f₂V²)Ę₂ where F₂ is the normal load on the tyre, f₂ = 2 x 10-6
and fo varies in terms of slip angle of tyres as in Figure Q1-2. If the car is
a rear-wheel drive, calculate:
Power losses at front wheels due to rolling resistance for slip angles
of 2.4º.
fo(-)
-3.6
-2.4
-1.2
0.03
0.025
0.02
0.015
0.01
0.005
0
0.0
a, (°)
1.2
2.4
3.6
Figure Q1-2 Variation of the rolling resistance coefficient fo of front wheels in
terms slip angle
Transcribed Image Text:b) The rolling resistance force at the contact patch of tyres is calculated as FRR = (fo+f₂V²)Ę₂ where F₂ is the normal load on the tyre, f₂ = 2 x 10-6 and fo varies in terms of slip angle of tyres as in Figure Q1-2. If the car is a rear-wheel drive, calculate: Power losses at front wheels due to rolling resistance for slip angles of 2.4º. fo(-) -3.6 -2.4 -1.2 0.03 0.025 0.02 0.015 0.01 0.005 0 0.0 a, (°) 1.2 2.4 3.6 Figure Q1-2 Variation of the rolling resistance coefficient fo of front wheels in terms slip angle
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