If a random variable X with the following distribution has mean value of 0.6, find30.1-12P(X=x)0.20.2ma) the value of m and the value of nb) P(X<=1)c) variance of Xd) expected value of Y=3X+1e) variance of Y=3X+1

We have given that Mean =0.6 E(x)= ∑x×p(x) E(x2)=∑x2×p(x) Var(x)=E(x2) - [E(x)]2 NOTE:- According…

a ra variable A föllowing distributie has nean lue of 0.0, Ilnd -101 2 | 3 P(X=x) 0.2 0.1 0.2 m ) the value of m and the value of n -) P(X<=1) ) variance of X ) expected value of Y=3X+1 ) variance of Y=3X+1

a ra variable A föllowing distributie has nean lue of 0.0, Ilnd -101 2 | 3 P(X=x) 0.2 0.1 0.2 m ) the value of m and the value of n -) P(X<=1) ) variance of X ) expected value of Y=3X+1 ) variance of Y=3X+1

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Question

100%

If a random variable X with the following distribution has mean value of 0.6, find
3
0.1
-1
2
P(X=x)
0.2
0.2
m
a) the value of m and the value of n
b) P(X<=1)
c) variance of X
d) expected value of Y=3X+1
e) variance of Y=3X+1

Expert Solution

Step 1

We have given that

Mean =0.6

E(x)= ∑x×p(x)

E(x²)=∑x²×p(x)

Var(x)=E(x²) - [E(x)]²

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