(a) P(Z ≤ −1.84) = (b) P(Z > -1.39) = (c) P (1.09 < Z < 2.19) =
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Suppose Z follows the standard
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![(a) P(Z < -1.84) =
(b) P(Z > −1.39) = 0
(c) P (1.09 < Z < 2.19) =](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F138b8a1e-9e74-4a14-aacf-9ba46d51b282%2F1792e66f-213d-47de-8544-70a73e1728d6%2Fdi0g7lb_processed.png&w=3840&q=75)
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- Assume that the distributions for the following scenarios are normal. Use the normal standard table to find the following probabilities. Fill in blanks, round z-scores to the nearest hundredth. 1) The average score on a math test is 75 with a standard deviation of 8. What is the probability that a randomly selected test has a score of 90 or higher? P(z > ______) = _________ 2) The life of a gas grill is 3.5 years with a standard deviation 0.35 years. What is the probability that the grill will last less than 3 years? P(z < -1.43) = _________ 3) Ambulance response times average 7.5 minutes with a standard deviation of 2.5. What is the probability that an ambulance will respond within 6 to 8 minutes. P(_____ < z < ______) = 0.3050Assume that the traffic to the web site of Smiley's People, Inc., which sells customized T-shirts, follows a normal distribution, with a mean of 6.5 million visitors per day and a standard deviation of 3 million visitors per day. What is the probability that the web site has more than 1.5 million visitors in a single day? Question 3 options: 0.7545 0.5543 0.9522 0.3454Assume you have a normal distribution representing the likelihood of project completion times. The mean of this distribution is 14, and the standard deviation is 4. The probability of completing the project in 15 or fewer days is: a. 0.59 b. 0.27 c. 0.93 d. 0.75
- Assume that the distributions for the following scenarios are normal. Use the normal standard table to find the following probabilities. Round z-scores to the nearest hundredth. 1. The average score on a math test is 75 with a standard deviation of 8. What is the probability that a randomly selected test has a score of 90 or higher? P(z 2. The life of a gas grill is 3.5 years with a standard deviation 0.35 years. What is the probability that the grill will last less than 3 years? P(z 3. Ambulance response times average 7.5 minutes with a standard deviation of 2.5. What is the probability that an ambulance will respond within 6 to 8 minutes. P(If z is a standard normal random variable, find the probability.The probability that z lies above 1.12The average student loan debt for college graduates is $25,200. Suppose that that distribution is normal and that the standard deviation is $13,300. Let X = the student loan debt of a randomly selected college graduate. Round all probabilities to 4 decimal places and all dollar answers to the nearest dollar. a. What is the distribution of X? X - N b Find the probability that the college graduate has between $22,700 and $29,650 in student loan debt. c. The middle 30% of college graduates' loan debt lies between what two numbers? Low: $ High: S
- If Z is a standard normal variable, find the probability. The probability that Z lies between 0 and 3.01If z is a standard normal random variable, find the probability.The probability that z lies above 2.13The average student loan debt for college graduates is $25,650. Suppose that that distribution is normal and that the standard deviation is $14,350. Let X = the student loan debt of a randomly selected college graduate. Round all probabilities to 4 decimal places and all dollar answers to the nearest dollar.b Find the probability that the college graduate has between $28,800 and $41,400 in student loan debt. c. The middle 20% of college graduates' loan debt lies between what two numbers? Low: $ High: $
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