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a pumpkin was thrust vertically upward with a speed of 28 ft/s from the top of a 35 foot high cliff. They calculated that the height (h) of the pumpkin above the ground, in feet, after t seconds is given by the formula h=-7t2+28t+35. a. when will the pumpkin pass the top of the 35 foot cliff on its way back down? h=35 b. when will the pumpkin hit the ground? h=0

a pumpkin was thrust vertically upward with a speed of 28 ft/s from the top of a 35 foot high cliff. They calculated that the height (h) of the pumpkin above the ground, in feet, after t seconds is given by the formula h=-7t2+28t+35. a. when will the pumpkin pass the top of the 35 foot cliff on its way back down? h=35 b. when will the pumpkin hit the ground? h=0

Elementary Geometry For College Students, 7e
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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a pumpkin was thrust vertically upward with a speed of 28 ft/s from the top of a 35 foot high cliff. They calculated that the height (h) of the pumpkin above the ground, in feet, after t seconds is given by the formula h=-7t2+28t+35.

a. when will the pumpkin pass the top of the 35 foot cliff on its way back down? h=35

b. when will the pumpkin hit the ground? h=0

Expert Solution
Step 1

Given that: height of pumpkin at any time t, h(t)=-7t2+25t+35

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