A pump is rated to deliver 50.0 gal/min. Find the velocity of the water in (a) a 6.00-in diameter pipe and a (b) 3.00-in diameter pipe. trioq 2+ 01 qu tol yab lei no ni di ci) ozzon ont brit

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Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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**Problem Statement:**

A pump is rated to deliver 50.0 gallons per minute (gal/min). Calculate the velocity of the water in:

(a) a 6.00-inch diameter pipe  
(b) a 3.00-inch diameter pipe.

**Instructions:**

To solve this problem, you can use the formula for flow rate and the cross-sectional area of a pipe:

1. **Flow Rate Equation:**  
   \( Q = A \times v \)  
   Where:  
   - \( Q \) is the flow rate (given as 50.0 gal/min).  
   - \( A \) is the cross-sectional area of the pipe.  
   - \( v \) is the velocity of the water.  

2. **Cross-Sectional Area of a Pipe:**  
   \( A = \pi \times \left(\frac{d}{2}\right)^2 \)  
   Where:  
   - \( d \) is the diameter of the pipe.  

3. **Convert Units if Necessary:**  
   - 1 gallon = 0.133681 cubic feet  
   - Diameter should be in the same units as the flow rate’s volume unit (if using gallons and inches, it needs to be consistent).  

**Steps:**

1. Calculate the cross-sectional area for each pipe.
2. Rearrange the flow rate formula to solve for velocity (\( v \)).
3. Compute the velocity for both (a) and (b).

**Considerations:**

Ensure all measurements and computations are unit-consistent to prevent errors. Use significant figures as required to match the precision given in the problem statement.
Transcribed Image Text:**Problem Statement:** A pump is rated to deliver 50.0 gallons per minute (gal/min). Calculate the velocity of the water in: (a) a 6.00-inch diameter pipe (b) a 3.00-inch diameter pipe. **Instructions:** To solve this problem, you can use the formula for flow rate and the cross-sectional area of a pipe: 1. **Flow Rate Equation:** \( Q = A \times v \) Where: - \( Q \) is the flow rate (given as 50.0 gal/min). - \( A \) is the cross-sectional area of the pipe. - \( v \) is the velocity of the water. 2. **Cross-Sectional Area of a Pipe:** \( A = \pi \times \left(\frac{d}{2}\right)^2 \) Where: - \( d \) is the diameter of the pipe. 3. **Convert Units if Necessary:** - 1 gallon = 0.133681 cubic feet - Diameter should be in the same units as the flow rate’s volume unit (if using gallons and inches, it needs to be consistent). **Steps:** 1. Calculate the cross-sectional area for each pipe. 2. Rearrange the flow rate formula to solve for velocity (\( v \)). 3. Compute the velocity for both (a) and (b). **Considerations:** Ensure all measurements and computations are unit-consistent to prevent errors. Use significant figures as required to match the precision given in the problem statement.
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