A publisher wants to estimate the mean length of time (in minutes) all adults spend reading newspapers. To determine this estimate, the publisher takes a random sample of 15 people and obtains the results below. From past studies, the publisher assumes σ is 2.2 minutes and that the population of times is normally distributed. 10 7 9 10 7 12 12 12 12 11 6 7 9 9 12 Question content area bottom Part 1 Construct the 90% and 99% confidence intervals for the population mean. Which interval is wider? If convenient, use technology to construct the confidence intervals. The 90% confidence interval is (enter your response here ,enter your response here ). (Round to one decimal place as needed.)
A publisher wants to estimate the mean length of time (in minutes) all adults spend reading newspapers. To determine this estimate, the publisher takes a random sample of 15 people and obtains the results below. From past studies, the publisher assumes σ is 2.2 minutes and that the population of times is normally distributed. 10 7 9 10 7 12 12 12 12 11 6 7 9 9 12 Question content area bottom Part 1 Construct the 90% and 99% confidence intervals for the population mean. Which interval is wider? If convenient, use technology to construct the confidence intervals. The 90% confidence interval is (enter your response here ,enter your response here ). (Round to one decimal place as needed.)
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
A publisher wants to estimate the mean length of time (in minutes) all adults spend reading newspapers. To determine this estimate, the publisher takes a random sample of 15 people and obtains the results below. From past studies, the publisher assumes
normally distributed.
σ
is
2.2
minutes and that the population of times is
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12
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11
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Question content area bottom
Part 1
Construct the 90% and 99% confidence intervals for the population mean. Which interval is wider? If convenient, use technology to construct the confidence intervals.
The 90% confidence interval is
(enter your response here
,enter your response here
).
(Round to one decimal place as needed.)Expert Solution
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