A publisher wants to estimate the mean length of time (in minutes) all adults spend reading newspapers. To determine this estimate, the publisher takes a random sample of 15 people and obtains the results below. From past studies, the publisher assumes o is 1.5 minutes and that the population of times is normally distributed. 7 10 8. 9. 9. 9. 11 6. 6. 9. 7 9. Construct the 90% and 99% confidence intervals for the population mean. Which interval is wider? If convenient, use technology to construct the confidence intervals. The 90% confidence interval is (, ). (Round to one decimal place as needed.)

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A publisher wants to estimate the mean length of time (in minutes) all adults spend reading newspapers.
To determine this estimate, the publisher takes a random sample of 15 people and obtains the results
below. From past studies, the publisher assumes o is 1.5 minutes and that the population of times is
normally distributed.
7 7
10
8
6
9 9
9.
11
6 7 6 9 7 9
Construct the 90% and 99% confidence intervals for the population mean. Which interval is wider? If
convenient, use technology to construct the confidence intervals.
The 90% confidence interval is (
). (Round to one decimal place as needed.)
Transcribed Image Text:A publisher wants to estimate the mean length of time (in minutes) all adults spend reading newspapers. To determine this estimate, the publisher takes a random sample of 15 people and obtains the results below. From past studies, the publisher assumes o is 1.5 minutes and that the population of times is normally distributed. 7 7 10 8 6 9 9 9. 11 6 7 6 9 7 9 Construct the 90% and 99% confidence intervals for the population mean. Which interval is wider? If convenient, use technology to construct the confidence intervals. The 90% confidence interval is ( ). (Round to one decimal place as needed.)
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