A psychologist investigated whether there is a difference, on average, in IQ scores for twins. She randomly selected 30 sets of twins from a database and measured their IQs. The mean difference (firstborn – second-born) was 2.1 points with a standard deviation of 7.2 points. Do the data provide a convincing evidence of a difference, on average, in IQ scores for twins? Do Perform the calculations, then complete the conclusion. Conclude Because the P-value, which is , is = 0.05, we H0. We convincing evidence of , on average, in IQ scores for twins.
A psychologist investigated whether there is a difference, on average, in IQ scores for twins. She randomly selected 30 sets of twins from a database and measured their IQs. The mean difference (firstborn – second-born) was 2.1 points with a standard deviation of 7.2 points. Do the data provide a convincing evidence of a difference, on average, in IQ scores for twins? Do Perform the calculations, then complete the conclusion. Conclude Because the P-value, which is , is = 0.05, we H0. We convincing evidence of , on average, in IQ scores for twins.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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A psychologist investigated whether there is a difference, on average, in IQ scores for twins. She randomly selected 30 sets of twins from a database and measured their IQs. The mean difference (firstborn – second-born) was 2.1 points with a standard deviation of 7.2 points. Do the data provide a convincing evidence of a difference, on average, in IQ scores for twins?
Do
Perform the calculations, then complete the conclusion.
Conclude
Because the P-value, which is
, is
= 0.05, we
H0. We
convincing evidence of
, on average, in IQ scores for twins.
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