A proton with a kinetic energy of 4.2 keV follows a circular path in a region where the magnetic field is uniform and has a magnitude of 60 mT. What is the radius of this path? (Note 1eV = 1.6*10-19 J, mp= 1.67*10-27 kg)

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A proton with a kinetic energy of 4.2 keV follows a circular path in a
region where the magnetic field is uniform and has a magnitude of
60 mT. What is the radius of this path?
(Note 1eV = 1.6*10 J, m,= 1.67*10-27
kg)
Transcribed Image Text:A proton with a kinetic energy of 4.2 keV follows a circular path in a region where the magnetic field is uniform and has a magnitude of 60 mT. What is the radius of this path? (Note 1eV = 1.6*10 J, m,= 1.67*10-27 kg)
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