A proton moving in a uniform magnetic field with ₁1.18 x106 m/s experiences force F₁ =1.27 x10-16 kN. A second proton with v₂ =2.13 x105 m/s experiences F₂-3.71 x10-16 * N in the same field. Submit Previous Answers Correct Correct answer is shown. Your answer 12.81-10-4 T(-1.281 mT) was either rounded differently or used a different number of significant figures than required for this part. Part B What is the direction of B? Give your answer as an angle measured ccw from the +z-axis.
A proton moving in a uniform magnetic field with ₁1.18 x106 m/s experiences force F₁ =1.27 x10-16 kN. A second proton with v₂ =2.13 x105 m/s experiences F₂-3.71 x10-16 * N in the same field. Submit Previous Answers Correct Correct answer is shown. Your answer 12.81-10-4 T(-1.281 mT) was either rounded differently or used a different number of significant figures than required for this part. Part B What is the direction of B? Give your answer as an angle measured ccw from the +z-axis.
College Physics
11th Edition
ISBN:9781305952300
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Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Question
![₁1.18 x10
A proton moving in a uniform magnetic field with
m/s experiences force
F₁1.27 x10-¹6 N. A second proton with
V₂=2.13 x10 m/s experiences
F₂ -3.71 x 10-16 N in the same field.
=
B = 1.28 mT
Submit
Correct
Correct answer is shown. Your answer 12.81-10-4 T(-1.281 mT) was
either rounded differently or used a different number of significant figures
than required for this part.
Part B
Previous Answers
What is the direction of B? Give your answer as an angle measured ccw from the
+x-axis.
Express your answer in degrees.
View Available Hint(s)
0= 58.3
Submit
VE ΑΣΦ
Previous Answers
Box
?
* Incorrect; Try Again; 9 attempts remaining
Check that the angle is measured specifically counterclockwise from the
positive z-axis.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F92ef1733-4d13-4c5f-b698-2777de49beac%2Fbef79ec2-ab98-433d-b573-2f0b4736374c%2F7d5tao_processed.png&w=3840&q=75)
Transcribed Image Text:₁1.18 x10
A proton moving in a uniform magnetic field with
m/s experiences force
F₁1.27 x10-¹6 N. A second proton with
V₂=2.13 x10 m/s experiences
F₂ -3.71 x 10-16 N in the same field.
=
B = 1.28 mT
Submit
Correct
Correct answer is shown. Your answer 12.81-10-4 T(-1.281 mT) was
either rounded differently or used a different number of significant figures
than required for this part.
Part B
Previous Answers
What is the direction of B? Give your answer as an angle measured ccw from the
+x-axis.
Express your answer in degrees.
View Available Hint(s)
0= 58.3
Submit
VE ΑΣΦ
Previous Answers
Box
?
* Incorrect; Try Again; 9 attempts remaining
Check that the angle is measured specifically counterclockwise from the
positive z-axis.
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