A proton moving in a circular path perpendicular to a constant magnetic field takes 1.00 µs to complete one revolution. Determine the magnitude of the magnetic field. Taken as q = 1.602x10-19 C and m= 1.67x10-27 kg for proton and t=3.14.

A proton moving in a circular path perpendicular to a constant magnetic field takes 1.00 µs to complete one revolution. Determine the magnitude of the magnetic field. Taken as q = 1.602x10-19 C and m= 1.67x10-27 kg for proton and t=3.14.

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Question

A proton moving in a circular path perpendicular to a constant magnetic field takes 1.00 us to
complete one revolution. Determine the magnitude of the magnetic field. Taken as q =
1.602x10-19 C and m = 1.67x1027 kg for proton and n=3.14.
O A) 0.0345 T
O B) 0.0143 T
C) 0.0124 T
D) 0.0154 T
E) 0.0327 T

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