A proton moving horizontally at 5.6 x 10^4 m/s enters a uniform magnetic field of 0.075 T directed upward at 40 degrees with the horizontal. Find the magnitude of the magnetic force acting on the proton.

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Chapter1: Units, Trigonometry. And Vectors
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Please answer the questions with complete and detailed solution. Use the international standard unit. I have attached the formula that we regularly use as a reference. Thank you!

A proton moving horizontally at 5.6 x 10^4 m/s enters a uniform magnetic field of 0.075
I directed upward at 40 degrees with the horizontal. Find the magnitude of the magnetic
force acting on the proton.
Transcribed Image Text:A proton moving horizontally at 5.6 x 10^4 m/s enters a uniform magnetic field of 0.075 I directed upward at 40 degrees with the horizontal. Find the magnitude of the magnetic force acting on the proton.
VOLTAGE DIVISION
THEOREM(VDT) FOR RESISTORS
CONNECTED IN SERIES
|q|B
W=
F
B=
qvsinė
m
E,
ту
r=
|q|B
f=
ER,
E,
R, +R2
R2
E,
ER2
É2 =
R, +R2
CURRENT DIVISION
THEOREM(CDT) FOR RESISTORS
CONNECTED IN PARALLEL
Magnetic Force on a Current-
Carrying Wire
F=BILsine
R2
R, +R2
mmf= NI
I,
H.
E,
R, R,
mmf= 0.4TNI
IR,
Ri +R2
r=
Ho
flux passing_P
B =
area
А
тmf_NI
F-qxv x Β
R =
HollyA
!!
R
R
Transcribed Image Text:VOLTAGE DIVISION THEOREM(VDT) FOR RESISTORS CONNECTED IN SERIES |q|B W= F B= qvsinė m E, ту r= |q|B f= ER, E, R, +R2 R2 E, ER2 É2 = R, +R2 CURRENT DIVISION THEOREM(CDT) FOR RESISTORS CONNECTED IN PARALLEL Magnetic Force on a Current- Carrying Wire F=BILsine R2 R, +R2 mmf= NI I, H. E, R, R, mmf= 0.4TNI IR, Ri +R2 r= Ho flux passing_P B = area А тmf_NI F-qxv x Β R = HollyA !! R R
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