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A proton moving eastward with a velocity of 5.0 km/s enters a magnetic field of 0.20 T pointing northward. What is the magnitude of the force that the
magnetic field exerts on the proton? (e = 1.60 × 10-19 C)
Hint: Remember the cross product of two vectors rule, this will help you to define the direction for force if needed, you will be using the same formula to calculate
FF = q(v ×.
Force =

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