A proton moving at 6.20 x 106 m/s through a magnetic field of magnitude 1.72 T experiences. magnetic force of magnitude 7.40 x 10-¹3 N. What is the angle between the proton's velocity and the field? (Enter both possible answers from smallest to largest. Enter only positive values between 0 and 360.) smaller value larger value Need Help? Read It Master It

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Chapter1: Units, Trigonometry. And Vectors
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### Problem Statement: Magnetic Force on a Proton

A proton moving at \(6.20 \times 10^6 \, \text{m/s}\) through a magnetic field of magnitude \(1.72 \, \text{T}\) experiences a magnetic force of magnitude \(7.40 \times 10^{-13} \, \text{N}\). What is the angle between the proton's velocity and the field? (Enter both possible answers from smallest to largest. Enter only positive values between 0 and 360.)

#### Inputs:
- **Velocity of the proton (\(v\))**: \(6.20 \times 10^6 \, \text{m/s}\)
- **Magnetic field (\(B\))**: \(1.72 \, \text{T}\)
- **Magnetic force (\(F\))**: \(7.40 \times 10^{-13} \, \text{N}\)

#### Outputs:
- **Smaller value of the angle (\(\theta\))**: [ ]
- **Larger value of the angle (\(\theta\))**: [ ]

#### Notes:
- Enter both possible answers from smallest to largest.
- Enter only positive values between 0 and 360.

#### Buttons:
- **Need Help?**
  - **Read It**
  - **Master It**

This problem involves calculating the angle between the velocity of a proton and the magnetic field it moves through, given the magnitude of the magnetic force acting on it. The required formula is based on the Lorentz force law for a charged particle in a magnetic field.
Transcribed Image Text:### Problem Statement: Magnetic Force on a Proton A proton moving at \(6.20 \times 10^6 \, \text{m/s}\) through a magnetic field of magnitude \(1.72 \, \text{T}\) experiences a magnetic force of magnitude \(7.40 \times 10^{-13} \, \text{N}\). What is the angle between the proton's velocity and the field? (Enter both possible answers from smallest to largest. Enter only positive values between 0 and 360.) #### Inputs: - **Velocity of the proton (\(v\))**: \(6.20 \times 10^6 \, \text{m/s}\) - **Magnetic field (\(B\))**: \(1.72 \, \text{T}\) - **Magnetic force (\(F\))**: \(7.40 \times 10^{-13} \, \text{N}\) #### Outputs: - **Smaller value of the angle (\(\theta\))**: [ ] - **Larger value of the angle (\(\theta\))**: [ ] #### Notes: - Enter both possible answers from smallest to largest. - Enter only positive values between 0 and 360. #### Buttons: - **Need Help?** - **Read It** - **Master It** This problem involves calculating the angle between the velocity of a proton and the magnetic field it moves through, given the magnitude of the magnetic force acting on it. The required formula is based on the Lorentz force law for a charged particle in a magnetic field.
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It said my larger value is incorrect by 10%, I am redoing the math but I have no luck.

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