A proton moving at 6.20 x 106 m/s through a magnetic field of magnitude 1.72 T experiences. magnetic force of magnitude 7.40 x 10-¹3 N. What is the angle between the proton's velocity and the field? (Enter both possible answers from smallest to largest. Enter only positive values between 0 and 360.) smaller value larger value Need Help? Read It Master It
A proton moving at 6.20 x 106 m/s through a magnetic field of magnitude 1.72 T experiences. magnetic force of magnitude 7.40 x 10-¹3 N. What is the angle between the proton's velocity and the field? (Enter both possible answers from smallest to largest. Enter only positive values between 0 and 360.) smaller value larger value Need Help? Read It Master It
Physics for Scientists and Engineers with Modern Physics
10th Edition
ISBN:9781337553292
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter28: Magnetic Fields
Section: Chapter Questions
Problem 41AP
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![### Problem Statement: Magnetic Force on a Proton
A proton moving at \(6.20 \times 10^6 \, \text{m/s}\) through a magnetic field of magnitude \(1.72 \, \text{T}\) experiences a magnetic force of magnitude \(7.40 \times 10^{-13} \, \text{N}\). What is the angle between the proton's velocity and the field? (Enter both possible answers from smallest to largest. Enter only positive values between 0 and 360.)
#### Inputs:
- **Velocity of the proton (\(v\))**: \(6.20 \times 10^6 \, \text{m/s}\)
- **Magnetic field (\(B\))**: \(1.72 \, \text{T}\)
- **Magnetic force (\(F\))**: \(7.40 \times 10^{-13} \, \text{N}\)
#### Outputs:
- **Smaller value of the angle (\(\theta\))**: [ ]
- **Larger value of the angle (\(\theta\))**: [ ]
#### Notes:
- Enter both possible answers from smallest to largest.
- Enter only positive values between 0 and 360.
#### Buttons:
- **Need Help?**
- **Read It**
- **Master It**
This problem involves calculating the angle between the velocity of a proton and the magnetic field it moves through, given the magnitude of the magnetic force acting on it. The required formula is based on the Lorentz force law for a charged particle in a magnetic field.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7fe3cb2f-b243-4382-966f-eceede055ec9%2F6e112cae-df12-4ee3-80ff-fb0d6a46883e%2Fz4n2zp7_processed.png&w=3840&q=75)
Transcribed Image Text:### Problem Statement: Magnetic Force on a Proton
A proton moving at \(6.20 \times 10^6 \, \text{m/s}\) through a magnetic field of magnitude \(1.72 \, \text{T}\) experiences a magnetic force of magnitude \(7.40 \times 10^{-13} \, \text{N}\). What is the angle between the proton's velocity and the field? (Enter both possible answers from smallest to largest. Enter only positive values between 0 and 360.)
#### Inputs:
- **Velocity of the proton (\(v\))**: \(6.20 \times 10^6 \, \text{m/s}\)
- **Magnetic field (\(B\))**: \(1.72 \, \text{T}\)
- **Magnetic force (\(F\))**: \(7.40 \times 10^{-13} \, \text{N}\)
#### Outputs:
- **Smaller value of the angle (\(\theta\))**: [ ]
- **Larger value of the angle (\(\theta\))**: [ ]
#### Notes:
- Enter both possible answers from smallest to largest.
- Enter only positive values between 0 and 360.
#### Buttons:
- **Need Help?**
- **Read It**
- **Master It**
This problem involves calculating the angle between the velocity of a proton and the magnetic field it moves through, given the magnitude of the magnetic force acting on it. The required formula is based on the Lorentz force law for a charged particle in a magnetic field.
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