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A proton moves through a magnetic field of magnitude 2.0 T at a speed of 5.00 x 106 m/s perpendicular to the field. Find the (a) centripetal acceleration and (b) radius of the circular path of the proton. 2. Given:

A proton moves through a magnetic field of magnitude 2.0 T at a speed of 5.00 x 106 m/s perpendicular to the field. Find the (a) centripetal acceleration and (b) radius of the circular path of the proton. 2. Given:

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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A proton moves through a magnetic field of magnitude 2.0 T at a speed of 5.00 x 106 m/s perpendicular to the field. Find the (a) centripetal acceleration and (b) radius of the circular path of the proton. 2. Given: B = 2.0 T; v = 5.00 x 106 m/s; Mass and charge of a proton: m = 1.67 x 10-27 kg' q = 1.60 x 10-19 C Solution and Answer: (a) The magnetic force is computed first. F = lq|vB sin 6 = |1.60 x 10-19 CI(5.00 x 106 m/s)(2 T) sin 90° F = 1.6 x 10-12 N Using Newton's second law of motion, 1.6 x 10-12 N m 1.67 x 10-27 kg = 9.58 × 1014 (b) Using the formula for centripetal acceleration a = v2 (5.00 x 106 m)² r = a 9.58 x 1014 m= 0.026 = 2.6 × 10-2 m
Transcribed Image Text:A proton moves through a magnetic field of magnitude 2.0 T at a speed of 5.00 x 106 m/s perpendicular to the field. Find the (a) centripetal acceleration and (b) radius of the circular path of the proton. 2. Given: B = 2.0 T; v = 5.00 x 106 m/s; Mass and charge of a proton: m = 1.67 x 10-27 kg' q = 1.60 x 10-19 C Solution and Answer: (a) The magnetic force is computed first. F = lq|vB sin 6 = |1.60 x 10-19 CI(5.00 x 106 m/s)(2 T) sin 90° F = 1.6 x 10-12 N Using Newton's second law of motion, 1.6 x 10-12 N m 1.67 x 10-27 kg = 9.58 × 1014 (b) Using the formula for centripetal acceleration a = v2 (5.00 x 106 m)² r = a 9.58 x 1014 m= 0.026 = 2.6 × 10-2 m
2. Refer to Sample Problem No. 2. Prove that r= 2.6 x 10-2 m using the equation %3D mv r=- Iq|B Show your solution and answer.
Transcribed Image Text:2. Refer to Sample Problem No. 2. Prove that r= 2.6 x 10-2 m using the equation %3D mv r=- Iq|B Show your solution and answer.
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