A proton moves in the magnetic field B= 0.42i T with a speed of 9.0 x 10° m/s in the directions shown in the figure. (Figure 1) Part A In figure (a), what is the magnetic force F on the proton? Give your answer in component form. Enter the z, y, and z components of the force separated by commas. x" x, IXI х-101 F,, F, F, = Submit Previous Answers Request Answer X Incorrect; Try Again; 14 attempts remaining Your answer implies that the vectors of the charged particle velocity and the magnetic field strength are collinear, which is not the case ao figure. Recall how a vector cross product is calculated and use the left-hand rule. You may need to review The Vector Cross Product. Part B In Figure (b), what is the magnetic force F on the proton? Give your answer in component form. Enter the z, y, and z components of the force separated by commas. ? Figure < 1 of 1> F., F,, F = Submit Request Answer (a) (b) Provide Feedback

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Proper Length

The theory of special relativity explains the connection between space and time to objects that move in a straight line at a constant speed. The objects move at the speed of light. When an object approaches light speed, its mass is endless and cannot move faster than light. The most crucial postulate of Einstein's special relativity is that the laws of nature do not change in each frame of reference.