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A proton moves at 7.51 ×10' m/s perpendicular to a magnetic field. The field proton to travel in a circular path causes the of radius 0.796 m. What is the field strength?

A proton moves at 7.51 ×10' m/s perpendicular to a magnetic field. The field proton to travel in a circular path causes the of radius 0.796 m. What is the field strength?

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A proton moves at 7.51 ×10' m/s perpendicular to a magnetic field. The field causes the proton to travel in a circular path of radius 0.796 m. What is the field strength?
Transcribed Image Text:A proton moves at 7.51 ×10' m/s perpendicular to a magnetic field. The field causes the proton to travel in a circular path of radius 0.796 m. What is the field strength?
a) At what speed will a proton move in a circular path of 4.25 m where the field strength is 0.96×10-5 T? m/s b) What would the radius of the path be if the proton had a speed of 7.4 x10® m/s? III
Transcribed Image Text:a) At what speed will a proton move in a circular path of 4.25 m where the field strength is 0.96×10-5 T? m/s b) What would the radius of the path be if the proton had a speed of 7.4 x10® m/s? III
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