A proton is placed in a uniform electric field of 2650 N/C. For related problem-solving tips and strategies, you may want. to view a Video Tutor Solution of Electron in a uniform field. ▾ Part B SET UP: A proton has charge +e and mass 1.67 x 10-27 kg. F (1.60 × 10-¹9 C)(2650 N/C) = 4.24 x 10-16 N. Calculate the proton's acceleration. Express your answer in meters per second squared. al speed. a = 2.5x10¹¹ m/s² Submit Previous Answers ✓ Correct a F 4.24x10-16N2.54 × 10¹1 m/s² = m 1.67x10-27 kg ▾ Part C V = Calculate the proton's speed after 1.40 us in the field, assuming it starts from rest. Express your answer in meters per second. 阿 VO ΑΣΦ yg ? m/s

A proton is placed in a uniform electric field of 2650 N/C. For related problem-solving tips and strategies, you may want. to view a Video Tutor Solution of Electron in a uniform field. ▾ Part B SET UP: A proton has charge +e and mass 1.67 x 10-27 kg. F (1.60 × 10-¹9 C)(2650 N/C) = 4.24 x 10-16 N. Calculate the proton's acceleration. Express your answer in meters per second squared. al speed. a = 2.5x10¹¹ m/s² Submit Previous Answers ✓ Correct a F 4.24x10-16N2.54 × 10¹1 m/s² = m 1.67x10-27 kg ▾ Part C V = Calculate the proton's speed after 1.40 us in the field, assuming it starts from rest. Express your answer in meters per second. 阿 VO ΑΣΦ yg ? m/s

University Physics Volume 2

18th Edition

ISBN:9781938168161

Author:OpenStax

Publisher:OpenStax

Chapter6: Gauss's Law

Section: Chapter Questions

Problem 51P: ne electric field at 2 cm from the center of long copper rod of radius 1 cm has a magnitude 3 N/C...

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Concept explainers

Electric Charges and Fields

One of the fundamental properties is the electromagnetic property. Charge cannot be destroyed by any process and this contributes formally to the law of charge conservation.

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A proton is placed in a uniform electric field of 2650 N/C.
For related problem-solving tips and strategies, you may want
to view a Video Tutor Solution of Electron in a uniform field.
Ting the mal speed.
Part B
-27
SET UP: A proton has charge +e and mass 1.67 × 10
F = (1.60 × 10-¹9 C)(2650 N/C) = 4.24 × 10-¹6 N.
Calculate the proton's acceleration.
Express your answer in meters per second squared.
a = 2.5x10¹¹ m/s²
Submit
V =
Correct
F
m
a =
Part C
Previous Answers
Submit
4.24x10-16 N
-= 2.54 × 10¹¹ m/s²
1.67×10 -27 kg
Calculate the proton's speed after 1.40 us in the field, assuming it starts from rest.
Express your answer in meters per second.
ΑΣΦ
ww
Previous Answers Request Answer
kg.
?
m/s

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