A proton is located at (0, 0, -3.5 x 10-9) m, and an alpha particle (consisting of two protons and two neutrons) is located at (4.0 x 10-9, 0, 2.0 x 10-9 m. (Express your answers in vector form.) (a) Calculate the force the proton exerts on the alpha particle. N (b) Calculate the force the alpha particle exerts on the proton. N
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- Referring to the image to the right, the mass of Block 1 is m1=3.72kgm1=3.72kg while the mass of Block 2 is m2=9.88kgm2=9.88kg. The coefficient of kinetic friction between Block 1 and the inclined surface is μk=0.39μk=0.39. The inclined surface is at an angle θ=32.2∘θ=32.2∘ above the horizontal. Part (a) Using the variables from the problem statement together with the acceleration due to gravity, gg, write an equation for the magnitude of the acceleration of the system. Hint: Based upon the numeric choices, Block 1 will accelerate up the incline while the suspended block, Block 2, accelerates vertically downward. Part (b) Calculate the magnitude, in meters per squared second, of the system's acceleration.A particle with mass m = 10 mg travels from the origin with initial velocity = 50 through a S uniform force field ♬ = (1002 + 3007) m.N. The particle impacts a vertical screen located at a = = 10 cm. Determine the y-coordinate of the impact location, and the speed of the particle at impact. Yimpact Vimpact = cm m m SAn electron with a speed of 1.10 × 107 m/s moves horizontally into a region where a constant vertical force of 3.70 × 10-16 N acts on it. The mass of the electron is 9.11 × 10-31 kg. Determine the vertical distance the electron is deflected during the time it has moved 27.0 mm horizontally. Number i Units ◆
- A object of mass 3.00 kg is subject to a force Fx that varies with position as in the figure below. A coordinate plane has a horizontal axis labeled x (m) and a vertical axis labeled Fx (N). There are three line segments. The first segment runs from the origin to (6,3). The second segment runs from (6,3) to (10,3). The third segment runs from (10,3) to (16,0). (a) Find the work done by the force on the object as it moves from x = 0 to x = 6.00 m. Your response differs from the correct answer by more than 10%. Double check your calculations. J(b) Find the work done by the force on the object as it moves from x = 6.00 m to x = 10.0 m. J(c) Find the work done by the force on the object as it moves from x = 10.0 m to x = 16.0 m. J(d) If the object has a speed of 0.600 m/s at x = 0, find its speed at x = 6.00 m and its speed at x = 16.0 m. speed at x = 6.00 m m/s speed at x = 16.0 m m/sProblem 18: A particle of mass 0.61 kg begins at rest and is then subject to a force in the positive x direction that changes with time as given by the following function: F = mg[1-e-3.1t ], where g is the acceleration due to gravity. Δv = 19.38 Determine the change in x-coordinate of the particle Δx between t = 0 and t = 2.3.A bullet is accelerated down the barrel of a gun by hot gases produced in the combustion of gun powder. What is the average force (in N) exerted on a 0.0500 kg bullet to accelerate it to a speed of 500 m/s in a time of 1.90 ms (milliseconds)? (Enter the magnitude.) N
- A object of mass 3.00 kg is subject to a force Fx that varies with position as in the figure below. A coordinate plane has a horizontal axis labeled x (m) and a vertical axis labeled Fx (N). There are three line segments. The first segment runs from the origin to (6,2). The second segment runs from (6,2) to (11,2). The third segment runs from (11,2) to (17,0). (a) Find the work done by the force on the object as it moves from x = 0 to x = 6.00 m. J(b) Find the work done by the force on the object as it moves from x = 6.00 m to x = 11.0 m. J(c) Find the work done by the force on the object as it moves from x = 11.0 m to x = 17.0 m. J(d) If the object has a speed of 0.450 m/s at x = 0, find its speed at x = 6.00 m and its speed at x = 17.0 m. speed at x = 6.00 m m/s speed at x = 17.0 m m/sIn the Bohr model of the hydrogen atom, an electron moves in a circular path around a proton. The speed of the electron is approximately 2.22 x 106 m/s. (a) Find the force acting on the electron as it revolves in a circular orbit of radius 0.530 x 10-10 m.Calculate the resultant ground reaction force during the inital contact phase (to the nearest whole number) given the following data vertical force Z =995 N and horizontal force X = -261 N Answer e to search E D Check C R F V Bi T G St 6 B H N J 8 M L O P₂ P ? ctri greeus / 3 pause 5°C Mostly cloudy # lock 7 home 4 Next page 1 12:15 30/11/2023 8