A proton is initially moving west at a speed of 1.05 x 106 m/s in a uniform magnetic field of magnitude 0.295 T directed vertically upward. Describe in detail the proton's trajectory, including its shape and orientation. the radius of the path the proton's trajectory --Select---

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### Understanding Proton Trajectories in Uniform Magnetic Fields

**Problem Statement:**

A proton is initially moving west at a speed of \(1.05 \times 10^6 \, \text{m/s}\) in a uniform magnetic field of magnitude \(0.295 \, \text{T}\) directed vertically upward. Describe in detail the proton’s trajectory, including its shape and orientation.

**Key Parameters:**
- Initial speed of the proton: \(1.05 \times 10^6 \, \text{m/s}\)
- Magnetic field strength: \(0.295 \, \text{T}\)
- Direction of magnetic field: Vertical (upward)

**Tasks:**
1. Determine the radius of the path.
2. Describe the proton's trajectory.

**Input Fields:**
1. **The radius of the path:** [Insert Input Box]
2. **The proton’s trajectory:** [Dropdown Menu - Select from options]

### Solution Approach

**Step 1: Understanding the Trajectory**
- When a charged particle such as a proton moves in a uniform magnetic field perpendicular to its velocity, it experiences a centripetal force that makes it move in a circular path.
- The trajectory of the proton in this case will be a circle perpendicular to the magnetic field, with the plane of the circle oriented horizontally.

**Step 2: Calculating the Radius**
- The radius of the path \(r\) can be found using the formula \(r = \frac{mv}{qB}\), where:
  - \(m\) is the mass of the proton (\(1.67 \times 10^{-27} \, \text{kg}\))
  - \(v\) is the velocity of the proton (\(1.05 \times 10^6 \, \text{m/s}\))
  - \(q\) is the charge of the proton (\(1.6 \times 10^{-19} \, \text{C}\))
  - \(B\) is the magnetic field strength (\(0.295 \, \text{T}\))

Insert these values to calculate the radius.

**Step 3: Describing the Trajectory**
- The proton moves in a circular trajectory in a plane perpendicular to the direction of the magnetic field.
- The proton's motion will be clockwise or counterclockwise depending on the direction of the magnetic force applied.

The detailed explanation includes
Transcribed Image Text:### Understanding Proton Trajectories in Uniform Magnetic Fields **Problem Statement:** A proton is initially moving west at a speed of \(1.05 \times 10^6 \, \text{m/s}\) in a uniform magnetic field of magnitude \(0.295 \, \text{T}\) directed vertically upward. Describe in detail the proton’s trajectory, including its shape and orientation. **Key Parameters:** - Initial speed of the proton: \(1.05 \times 10^6 \, \text{m/s}\) - Magnetic field strength: \(0.295 \, \text{T}\) - Direction of magnetic field: Vertical (upward) **Tasks:** 1. Determine the radius of the path. 2. Describe the proton's trajectory. **Input Fields:** 1. **The radius of the path:** [Insert Input Box] 2. **The proton’s trajectory:** [Dropdown Menu - Select from options] ### Solution Approach **Step 1: Understanding the Trajectory** - When a charged particle such as a proton moves in a uniform magnetic field perpendicular to its velocity, it experiences a centripetal force that makes it move in a circular path. - The trajectory of the proton in this case will be a circle perpendicular to the magnetic field, with the plane of the circle oriented horizontally. **Step 2: Calculating the Radius** - The radius of the path \(r\) can be found using the formula \(r = \frac{mv}{qB}\), where: - \(m\) is the mass of the proton (\(1.67 \times 10^{-27} \, \text{kg}\)) - \(v\) is the velocity of the proton (\(1.05 \times 10^6 \, \text{m/s}\)) - \(q\) is the charge of the proton (\(1.6 \times 10^{-19} \, \text{C}\)) - \(B\) is the magnetic field strength (\(0.295 \, \text{T}\)) Insert these values to calculate the radius. **Step 3: Describing the Trajectory** - The proton moves in a circular trajectory in a plane perpendicular to the direction of the magnetic field. - The proton's motion will be clockwise or counterclockwise depending on the direction of the magnetic force applied. The detailed explanation includes
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