A proton is initially at rest. At time t = 0,it is accelerated upward with an accelerationof 1.8 x 10¹8 m/s2 for a very short time. Wemake observations at location A, 17 m fromthe proton as in the figure below.a = 1.8 × 10¹8 m/s²1• Protonㅏ-- 17 mATake the +r direction to be toward theright, the +y direction to be upward, and the+z direction to be out of the page (towardyou).What is the direction of the radiativeelectric field at location A at time t =5.66667 x 10-8 s? Choose the unit vectorcorresponding to this direction.

At time t=0,Acceleration a=1.8×1018m/s2 At time t=5.66667×10-8 s, The direction of radiative…

Answered: A proton is initially at rest. At time…

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