A proton initially has v = 3.0i – 9.0 j + 2.0k and then 4.0 s later has v = -9.0i – 9.0j + 3.0k (in meters per second). (a) For that 4.0 s, what is the proton's average acceleration aava in unit-vector notation? ava = -1.5i – 0.25k m/s² (b) For that 4.0 s, what are the magnitude and direction of aavg? magnitude 1.52 X m/s² direction -189.5 ° (from the +x axis in the xz plane)

College Physics
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ISBN:9781305952300
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Chapter1: Units, Trigonometry. And Vectors
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i followed examples in the textbook but i still am deducing the wrong answer :( but somehow i’m getting the right direction value
A proton initially has v = 3.0i – 9.0 j + 2.0k and then 4.0 s later has v = -9.0i – 9.0j + 3.0k (in meters per second).
(a) For that 4.0 s, what is the proton's average acceleration aava in unit-vector notation?
davg
-1.5i – 0.25k
m/s²
(b) For that 4.0 s, what are the magnitude and direction of åavg?
magnitude
1.52
X m/s²
direction
-189.5
° (from the +x axis in the xz plane)
Transcribed Image Text:A proton initially has v = 3.0i – 9.0 j + 2.0k and then 4.0 s later has v = -9.0i – 9.0j + 3.0k (in meters per second). (a) For that 4.0 s, what is the proton's average acceleration aava in unit-vector notation? davg -1.5i – 0.25k m/s² (b) For that 4.0 s, what are the magnitude and direction of åavg? magnitude 1.52 X m/s² direction -189.5 ° (from the +x axis in the xz plane)
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