A proton enters the region of a uniform electric field (E = 200 N/C). Find the acceleration of the proton. (Charge of the proton: q = 1.6x10^–19 C, mass of the proton: m= 1.6x10^-27 kg) %3|
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Q: A proton enters the region of a uniform electric field (E = 200 N/C). Find the acceleration of the…
A: Data provided: Electric field (E) = 200 N/C Charge (q) = 1.6×10-19 C Mass (m) = 1.6×10-27 kg
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- Some possibly useful numbers = 8.99 x 10° N-m²/C² €0 = 8.85 × 10-12C²/Nm² e = 1.6 × 10–19 C = 9.11 × 10-31kg mp = 1.67 x 10–27kg leV 1.6 x 10-19J %3DOn the x axis, a point charge Q = +4.55E-6 C is placed at the origin x = 0.00 m. What is the electric field E at x = –2.82 m (in N/C; use positive sign if E points in the +x direction, and negative sign if E points in the –x direction)?蛋白 A ball of conductor of radius RE = 3 m carries charge 2Q. Inside, it has an empty concentric spherical cavity of radius R₁ = 1.2 m. Find the charge q at radius R₁ and supply the missing numerical factor below. 9 = (_______ JQ
- A projectile is fired from 3 meters height above level ground with an initial velocityequals to 20 m/s and at an angle equals to 30 degrees above the horizontal level. Notethat the air resistance is neglected. the position of a particle with respect to time is defined by:r(t) = rcos(cot )i +rsin(cot)j ,where 7 and c are constants.Demonstrate that the magnitude of the acceleration of the particle is constant.Two point charges of magnitude +10 μC and - 30 μC are placed 1 meter from each other. Calculate the magnitude of the Net Force on a proton (charge = 1.6x10-19 C) that is placed directly between the two charges.(2-10) A charge q1 = -5 µC is located at (x,y)=(0,3) m. Another charge of q2 = +4 µC is located at (4.5,3) m. O (0,0)
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