A projectile is shot with a speed of 15.3 m/s at an upward angle of 69.9° from the top of a cliff 22.5 m high. How long does it take the projectile to hit the ground? Express your answer in seconds to 3 significant figures. Use g=9.81 m/s2.
A projectile is shot with a speed of 15.3 m/s at an upward angle of 69.9° from the top of a cliff 22.5 m high. How long does it take the projectile to hit the ground? Express your answer in seconds to 3 significant figures. Use g=9.81 m/s2.
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
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Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Transcribed Image Text:A projectile is shot with a speed of 15.3 m/s at an upward angle of 69.9° from the
top of a cliff 22.5 m high. How long does it take the projectile to hit the ground?
Express your answer in seconds to 3 significant figures. Use g=9.81 m/s2.
Expert Solution

Step 1
Given data
The speed of the projectile shot is v = 15.3 m/s.
The angle of projection from the top of the cliff is: H = 22.5 m
The angle of projection is: θ = 69.9°
The expression for the vertical distance moved by the projectile when projected and reach to the ground is given as:
Here g is taken as acceleration due to gravity, and t is taken to reach the ground.
When the projectile reaches the ground, the vertical distance is zero.
Y = 0
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