A projectile is shot with a speed of 15.3 m/s at an upward angle of 69.9° from the top of a cliff 22.5 m high. How long does it take the projectile to hit the ground? Express your answer in seconds to 3 significant figures. Use g=9.81 m/s2.

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A projectile is shot with a speed of 15.3 m/s at an upward angle of 69.9° from the
top of a cliff 22.5 m high. How long does it take the projectile to hit the ground?
Express your answer in seconds to 3 significant figures. Use g=9.81 m/s2.
Transcribed Image Text:A projectile is shot with a speed of 15.3 m/s at an upward angle of 69.9° from the top of a cliff 22.5 m high. How long does it take the projectile to hit the ground? Express your answer in seconds to 3 significant figures. Use g=9.81 m/s2.
Expert Solution
Step 1

Given data

The speed of the projectile shot is v = 15.3 m/s.

The angle of projection from the top of the cliff is: H = 22.5 m

The angle of projection is: θ = 69.9°

 

The expression for the vertical distance moved by the projectile when projected and reach to the ground is given as:

Physics homework question answer, step 1, image 1

Here g is taken as acceleration due to gravity, and t is taken to reach the ground.

When the projectile reaches the ground, the vertical distance is zero.

Y = 0

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