A projectile is shot at a hill, the base of which is 300 m away. The projectile is shot at 60° above thehorizontal with an initial speed of 75 m/s. The hill can be approximated by a plane sloped at 20° to thehorizontal. Relative to the coordinate system shown in the figure, the equation of this straighty = (tan 20°) x - 109. Where on the hill does the projectile land?75 m/s60⁰y = (tan 20°)x - 109-300 m-20⁰

We have to determine the direction the projectile will land on the hill. We know, s=300 m, θ=60°v=75…

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