A professor who teaches a large introductory statistics class (197 students) with eight discussion sections would like to test if student performance differs by discussion section, where each discussion section has a different teaching assistant. The summary table below shows the average final exam score for each discussion section as well as the standard deviation of scores and the number of students in each section. Sec 1 Sec 2 Sec 3 Sec 4 Sec 5 Sec 6 Sec 7 Sec 8 33 19 10 29 33 10 32 31 X¡ 92.94 91.11 91.8 92.45 89.3 88.3 90.12 93.45 Si 4.21 5.58 3.43 5.92 9.32 7.27 6.93 4.57 The ANOVA output below can be used to test for differences between the average Scores from the different discussion sections. Df Sum Sq Mean Sq F value Pr(>F) 1.87 0.0767 section 7 525.01 75 residuals 189 7584.11 Conduct a hypothesis test to determine if these data provide conyincing ouidongn 40.13 that t
A professor who teaches a large introductory statistics class (197 students) with eight discussion sections would like to test if student performance differs by discussion section, where each discussion section has a different teaching assistant. The summary table below shows the average final exam score for each discussion section as well as the standard deviation of scores and the number of students in each section. Sec 1 Sec 2 Sec 3 Sec 4 Sec 5 Sec 6 Sec 7 Sec 8 33 19 10 29 33 10 32 31 X¡ 92.94 91.11 91.8 92.45 89.3 88.3 90.12 93.45 Si 4.21 5.58 3.43 5.92 9.32 7.27 6.93 4.57 The ANOVA output below can be used to test for differences between the average Scores from the different discussion sections. Df Sum Sq Mean Sq F value Pr(>F) 1.87 0.0767 section 7 525.01 75 residuals 189 7584.11 Conduct a hypothesis test to determine if these data provide conyincing ouidongn 40.13 that t
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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
Transcribed Image Text:Ald/Scho...
Grad Schools
A professor who teaches a large introductory statistics class (197 students) with eight
discussion sections would like to test if student performance differs by discussion
section, where each discussion section has a different teaching assistant. The
summary table below shows the average final exam score for each discussion section
as well as the standard deviation of scores and the number of students in each
section.
Sec 1
Sec 2 Sec 3
Sec 4
Sec 5
Sec 6
Sec 7
Sec 8
nj
33
19
10
29
33
10
32
31
Xi 92.94
91.11
91.8
92.45
89.3
88.3
90.12
93.45
Si
4.21
5.58
3.43
5.92
9.32
7.27
6.93
4.57
The ANOVA output below can be used to test for differences between the average
Scores from the different discussion sections.
Df
Sum Sq Mean Sq F value Pr(>F)
section
7
525.01
75
1.87
0.0767
residuals
189
7584.11
40.13
Conduct a hypothesis test to determine if these data provide convincing evidence
that the average score varies across some (or all) groups. Check conditions and
describe any assumptions you must make to proceed with the test.
(a) Write the hypotheses for evaluating if there is a difference between average
Scores across sections in your own words.
O Ho: H1 = = ... = H8
Ha: At least one pair of means is the same
O Ho: µ1 = P2 = ... = P8
Ha: At least one of the means is different
O Ho: H1 = P2 = ...
= 48
Ha: µ1 * P2 # ... ² µg
(b) Assume that the conditions required for this inference are satisfied.
(c) What is the test statistic associated with this ANOVA test?
(please round to two decimal places)
(d) What is the p-value associated with this ANOVA test?
(please round to four decimal places)
(e) Interpret the conclusion of the test in the context of the study:
O Since p 2 0.05, there is enough evidence to claim a difference in average scores
across the different sections
O Since p 2 0.05, there is no difference in average scores across the different
sections
O Since p is close to 0.05, we cannot make a decision
OSince p 005 we do not have onouab evidence to claim a difference in average
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